8/9 = 0,8
0,8/4 = 0,2
so each piece was 0,2 yard long
Answer:
Given a square ABCD and an equilateral triangle DPC and given a chart with which Jim is using to prove that triangle APD is congruent to triangle BPC.
From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.
Therefore, the justification to complete Jim's proof is "SAS postulate"
Step-by-step explanation:
To simplify the process of expanding a binomial of the type (a+b) n (a + b) n, use Pascal's triangle. The same numbered row in Pascal's triangle will match the power of n that the binomial is being raised to.
A triangular array of binomial coefficients known as Pascal's triangle can be found in algebra, combinatorics, and probability theory. Even though other mathematicians studied it centuries before him in India, Persia, China, Germany, and Italy, it is called after the French mathematician Blaise Pascal in a large portion of the Western world. Traditionally, the rows of Pascal's triangle are listed from row =0 at the top (the 0th row). Each row's entries are numbered starting at k=0 on the left and are often staggered in relation to the numbers in the next rows. The triangle could be created in the manner shown below: The top row of the table, row 0, contains one unique nonzero entry.
Learn more about triangle here
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Answer:
f(x)=x(x-5)(x+2)
Step-by-step explanation:
Since the steps of the factorization of the polynomial f(x) is not given, I will proceed to give the correct factorization of f(x).
f(x)=x³-3x²-10x
First, we factor out x since it is a common term.
f(x)=x(x²-3x-10)
Next, we factorize the quadratic expression x²-3x-10.
f(x)=x(x²-5x+2x-10)
f(x)=x(x(x-5)+2(x-5))
f(x)=x(x-5)(x+2)
The correct factorization of the polynomial f(x)=x³-3x²-10x is: f(x)=x(x-5)(x+2)
The answer is 18.
Just replace the x with 2
