Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.




A score of 150.25 is necessary to reach the 75th percentile.
Factors are the numbers another number can be divided from. example-
8÷4=2, 4 is a factor of 8.
so the factors of 4 are 1,2and 4itself. like this-
4×1=4
1×4=4
2×2=4
answer- 1,2 and 4.
The answer is 984.6 hope this helps
Answer:
8
Step-by-step explanation:
Even though we don't know the number yet, let's name this number "n".
8n + 3 = 6n + 19
8n + 3 - 6n = 6n + 19 - 6n
2n + 3 = 19
2n = 16
n = 16/2
n = 8
Our number is 8.
Note: This answer is 100% correct.