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3 years ago

14

you are playing the integer game with your friends. you have drawn a -2 and -3 from the deck. when you add the numbers on these

cards together what is your answer.

1 answer:

ahrayia [7]3 years ago

4 0

Answer:

Bb

Step-by-step explanation:

Njkkmknb

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A certain test preparation course is designed to help students improve their scores on the GMAT exam. A mock exam is given at th

Bogdan [553]

Answer:

95% confidence interval for the average net change is between a lower limit of 11.709 and an upper limit of 30.921.

The critical value that should be used in constructing the confidence interval is 4.303.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = (17+20+26)/3 = 63/3 = 21

sd = sqrt[((17-21)^2 + (20-21)^2 + (26-21)^2) ÷ 3] = sqrt(42÷3) = sqrt(14) = 3.74

n = 3

degree of freedom = n-1 = 3-1 = 2

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (t) corresponding to 2 degrees of freedom and 5% significance level is 4.303.

The critical value is 4.303

E = t×sd/√n = 4.303×3.74/√3 = 9.291

Lower limit of mean = mean - E = 21 - 9.291 = 11.709

Upper limit of mean = mean + E = 21 + 9.291 = 30.291

95% confidence interval is (11.709, 30.391)

8 0

3 years ago

What is the correct answer of 2+2*3+2*2+4=?

Diano4ka-milaya [45]

2+2*3+2*2+4
=2+6+4+4
=16

5 0

3 years ago

Read 2 more answers

Does anyone know how to do this ?

Leni [432]

Answer:20

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =

sveta [45]

Answer:

$\displaystyle n^3-\frac{1}{n^{2}}$

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

$(a^x)^y=(a^y)^x=a^{xy}$

$\displaystyle a^{-x}=\frac{1}{a^x}$

We are given the expression:

$2^m=n$

We need to express the following expression in terms of n.

$8^m-4^{-m}$

It's necessary to modify the expression to use the given equivalence.

Recall $8=2^3 \text{ and }4 = 2^2$ . Thus:

$(2^3)^m-(2^2)^{-m}$

Applying the property:

$(2^m)^3-(2^m)^{-2}$

Substituting the given expression:

$n^3-n^{-2}$

Or, equivalently:

$\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}$

5 0

3 years ago

Solve:<br><br> x^2 = 81<br><br> x^2 = -9 <br><br> x^2 = 20<br><br> 3x^2 = 125

sergeinik [125]

<span>x^2 = 81
x = </span>±√81
x = ±9<span>

x^2 = -9 no solutions

x^2 = 20
x = </span>±√20
x = <span>±2</span>√5<span>

</span> $3x^2 = 125 \\ 
x^2 = \frac{125}{3} \\ x=б \sqrt{ \frac{125}{3} }$ <span>
</span>

3 0

3 years ago