Answer: the probability that the mean price for the sample was between $3.781 and $3.811 that week is 0.94122
Step-by-step explanation:
Given that;
sample size n = 32
mean μ = $3.796
standard deviation σ = 0.045
P(3.781 < x" < 3.811) = ?
Standard Error S.E = σ/√n = 0.045/√32 = 0.007955
z value for 3.781, z = x-μ/S.E = (3.781-3.796)/0.007955 = -1.8856 ≈ -1.89
z value for 3.811, z = x-μ/S.E = (3.811-3.796)/0.007955 = 1.8856 ≈ 1.89
P(3.781 < x" < 3.811) = P( -1.89 < z < 1.89)
= P(z < 1.89) - P(z < -1.89)
from z-score table
⇒ 0.9706 - 0.02938
⇒ 0.94122
Therefore the probability that the mean price for the sample was between $3.781 and $3.811 that week is 0.94122
Answer: 42/10
Step-by-step explanation:Since the value for c is known, we substitute it into the equation. Therefore, 1/2 * 42/5 = 42/10
Yes, the chance of getting tails when flipping a coin is 1/2.
We would simplify each bracket.
For the first bracket,
2 + 4 = 6
For the second bracket, 8 * 1000 = 8000
For the third bracket, 700/5 = 140
The expression becomes
6*8000*140 = 6720000
