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almond37 [142]
3 years ago
12

Find slope of a line perpendicular to each given

Mathematics
1 answer:
statuscvo [17]3 years ago
5 0
82 is the answer now sub to pooi thegreat on yt
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Write the expression |5x - 4| without absolute value signs
Leokris [45]

Answer:

Step-by-step explanation:

Basically those lines next to the problem are absolute value signs. Get rid of those then your problem is solved.

8 0
2 years ago
ANSWER THIS PLS!!!!
astra-53 [7]

Answer and Step-by-step explanation: With the constant velocity motion formula, we can determine constant velocity of the object in motion whose data we collected:

x = x₀ + vt

Velocity can be calculated as:

v=\frac{x-x_{0}}{t}

v=\frac{70-40}{10}

v = 3 m/s

The beginning of the data collect, object is 40m away, then x₀ = 40.

So, equation modeling the object's path is x = 40 + 3t.

5 0
3 years ago
FInd the surface area of the triangular prism
Marta_Voda [28]

Answer:

273.7

Step-by-step explanation:

first fine the sides that isn't the base.

triangle area formula: (b*h)/2

(14*9)/2 = 63

since there are 3 sides you multiply this by three.

63*3=189

then find the base.

same formula since its a triangle.

(12.1*14)/2 = 84.7

now add them both up:

84.7+189 = 273.7

hope this helps!

3 0
3 years ago
Read 2 more answers
PLEASE HELP!<br>Calculate $40^{13} \pmod{85}.$
SVEN [57.7K]
In this type of calculations, we decompose 13 by checking the lowest powers of the base, that is 40. for example we check 40^2, or 40^3 and compare it to 85

Notice

40*40*40=64,000

so we check how many time does 85 fit into 64,000:

64,000/85=752.94

85*753=64,005;       64000-64,005=-5

this means that 

40^{3} =-5\pmod{85}

thus

40^{13} =40^{3*4+1}={(40^{3})}^{4}*40=(-5)^{4}*40 \pmod{85}=\\\\625*40\pmod{85}=(7*85+30)*40\pmod{85}=30*40\pmod{85}\\\\=1200\pmod{85}=(14*85+10)\pmod{85}=10\pmod{85}


Answer: 10 (mod85)

Remark, the set of all solutions is:

{......-75, 10, 95, .....}, that is 85k +10
7 0
3 years ago
Please help marking brainliest if it's correct and explain​
yarga [219]
Imma take a guess maybe C
4 0
3 years ago
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