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Lena [83]
3 years ago
5

Engineers are analyzing the performance of windshield wiper blades. At the end of one swipe, the tip of a blade is at (−5, 7) wh

en represented graphically. What is the sine value of this function?

Mathematics
1 answer:
USPshnik [31]3 years ago
7 0

Answer:

\frac{7}{\sqrt{74} }

Step-by-step explanation:

Please look at the attached photo for your information

Sine value = \frac{Height}{hypotenuse} but here we know that the tip of a blade is at (−5, 7)

=>  Heigh = 7 (the value of y)

=> Hypotenuse = \sqrt{7^{2} + 5^{2}  } = \sqrt{74}

We substitute two values have just been found in the sine value fomula:

\frac{7}{\sqrt{74} }

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Is this pair of fractions &lt;, &gt;, or =<br><br> 6/7 and 7/8
miskamm [114]
It would be > cause it is a smaller fraction which makes the decimal a bigger number 
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5 0
3 years ago
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If the original price is $40.00 and the percent of markup is 8% what is the value of the markup ?
Ne4ueva [31]
Answer=$3.20

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$40.00*0.08=$3.20

The markup was $3.20 
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3 years ago
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David sent a survey to 12 classmates. One week laterb9 of the surveys were returned what percent of the surveys were returned
Olegator [25]
9 of 12 were returned which is the same as 9/12. Reduce the fraction...

9/12 = 3/4

To find percent we need the denominator to equal 100 so if we multiply by 25/25...

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75%
4 0
3 years ago
Justify each step of the proof.
WARRIOR [948]
 <span>I assume that the x is squared 
(on Yahoo!Answers, we often use the caret ^ to show a power or an exponent) 
(think of it as a tiny arrow pointing up, showing that the following number should be seen as if it were raised above the line) 

2(x^2 + 5) = 60 

Can it be x = 5 ? 
we test: 
2(5^2 + 5) = 2(25 + 5) = 2(30) = 60 
it works, therefore x = 5 is a solution. 

Can it be x = -5? 
we test again: 
2[(-5)^2 + 5) = 2(25 + 5) = 2(30) = 60 
it works, therefore x = -5 is also a solution. 

The way you did it, there could be some confusion between step 4 and step 5 (because you do not explain how you go from 4 to 5). 
If you simply "take the square root" on both sides, someone could argue that the "principal" square root of a number is the positive value (+5 only, not -5). On the other hand, if you state: 
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The way the conjecture is stated at the beginning, the easiest way is to check both values to find out that, yes, they are both valid solutions.</span>
7 0
4 years ago
Please help me, and please explain how you get to the answer.
patriot [66]

Your answer is C) 2a² + 2b²

To find this we can just expand the brackets of (a - b)² and (a + b)², and then combine like terms:

(a - b)² = (a - b)(a - b) = a² - 2ab + b²

(a + b)² = (a + b)(a + b) = a² + 2ab + b²

Then when you combine like terms, you get (a² + a²) + (-2ab + 2ab) + (b² + b²), so the ab terms cancel out and you get left with 2a² + 2b².

I hope this helps!

4 0
3 years ago
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