Answer:
(x+1)(x+3)
Step-by-step explanation:
Let's factor x^2+4x+3
x^2+4x+3
The middle number is 4 and the last number is 3.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get 4
Multiply together to get 3
Can you think of the two numbers?
Try 1 and 3:
1+3 = 4
1*3 = 3
Fill in the blanks in
(x+_)(x+_)
with 1 and 3 to get...
(x+1)(x+3)
Answer:I don’t understand too
Step-by-step explanation:
Sorry I can’t help you
The length of one of the remaining sides is 34.20 meters.
<h3>What is the length?</h3>
A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs
Perimeter of an isosceles trapezoid = sum of lengths of sides of a trapezoid
length of shorter base + length of longer base + (2 x legs)
108 = 11.5 + 28.1 + (2 x legs)
108 = 39.60 + (2 x legs)
108 - 39.60 = (2 x legs)
68.40 = (2 x legs)
leg = 68.40 / 2
= 34.20 meters
To learn more about trapezoids, please check: brainly.com/question/25748893
#SPJ1
Answer:
StartFraction 50 miles Over 1 hour EndFraction = StartFraction 200 miles Over question mark hours EndFraction
Step-by-step explanation:
For constant speed, miles and hours are proportional. One possible equation is ...

_____
<em>Comment on the solution</em>
I personally like to put the unknown in the numerator, so the equation can be solved in one step. The equation above requires two steps: one to cross-multiply, and one to divide by 50.
I might write the equation as ...
(? hours)/(200 mi) = (1 hour)/(50 mi) . . . . multiply by 200 mi to solve
Another way to write the equation is matching the ratios of times to corresponding miles:
(? hours)/(1 hour) = (200 mi)/(50 mi)
This only requires simplification to solve it: ? = 4.
Answer:
2.35%
Step-by-step explanation:
Mean number of months (M) = 39 months
Standard deviation (S) = 10 months
According to the 68-95-99.7 rule, 95% of the data is comprised within two standard deviations of the mean (39-20 to 39+20 months), while 99.7% of the data is comprised within two standard deviations of the mean (39-30 to 39+30 months).
Therefore, the percentage of cars still in service from 59 to 69 months is:

The approximate percentage of cars that remain in service between 59 and 69 months is 2.35%.