(3x²-2x-4)(2x²+x-3)=3x²(2x²+x-3)-2x(2x²+x-3)-4(2x²+x-3)=
=6x⁴+3x³-9x²-(4x³+2x²-6x)-(8x²+4x-12)=
=6x⁴+3x³-9x²-4x³-2x²+6x-8x²-4x+12=
=6x⁴-x³-x²+2x+12
Answer:
C
Step-by-step explanation:
This is the only possible correct answer because the other three all show the final price as 0.90x, which is correct since the price is the normal one minus 10 percent. C is incorrect because it suggests the normal price has a 10% tax, or extra value on it.
You divide by -7 on both sides then add three to both sides and the answer is -3
Treat
as the boundary of the region
, where
is the part of the surface
bounded by
. We write
with
.
By Stoke's theorem, the line integral is equivalent to the surface integral over
of the curl of
. We have
so the line integral is equivalent to
where
is a vector-valued function that parameterizes
. In this case, we can take
with
and
. Then
and the integral becomes
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