C(8)=29 you have to plug in 8 for n in the equation and solve. Hope this helps!!!
You want to find values of v (number of visors sold) and c (number of caps sold) that satisfy the equation
... 3v + 7c = 4480
In intercept form, this equation is
... v/(1493 1/3) + c/640 = 1 . . . . . divide by 4480
Among other things, this tells us one solution is
... (v, c) = (0, 640)
The least common multiple of 3 and 7 is 21, so decreasing the number of caps sold by some multiple of 3 and increasing the number of visors sold by that same multiple of 7 will result in another possible solution.
The largest multiple of 21 that is less than 4480 is 213. Another possible solution is (0 +213·7, 640 -213·3) = (1491, 1)
We can also pick some number in between, say using 100 as the multiple
... (0 +100·7, 640 -100·3) = (700, 340)
In summary, your three solutions could be
... (visors, caps) = (0, 640), (700, 340), (1491, 1)
Add it tighter and it will make ur number then subtract that
Total number of cakes made by Simon = 30 cakes.
Number of cakes gave to Sali = 1/5 Of total cakes = 1/5 * 30 = 6 cakes.
Number of the cakes gave to Jane = 10% of 30 cakes
10% can be written as 10/100 in fracions and in decimals it would be 0.10.
Therefore, 10% of 30 cakes = 0.10 times 30 = 3 cakes.
Total number of cakes left = Total cakes made - Cakes gave to Sali - Cakes gave to Jane = 30-6-3
Therefore, Total number of cakes left = 21.
21 cakes left our of 30 cakes.
21 out of 30 could be written in fracion form as 21/30.
We can reduce this fracion in simplest form by dividing top and bottom by 3, we get
7/10.
Therefore, 7/10 fraction of the cakes does he have left.
Answer:
36
Step-by-step explanation:
