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Serjik [45]
3 years ago
5

3a+2d^2-14+6a-4d-2d^2

Mathematics
2 answers:
Ghella [55]3 years ago
7 0
So 2d^2 and -2d^2 cancel each other out and then that leaves

3a-14+6a-4d collect like terms

9a-14-4d

And that’s the answer
qwelly [4]3 years ago
4 0
Collect like terms:
(3a+6a)+(2d^2-2d^2)-14-4d

Then simplify and you get:
9a-14-4d
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Use Gaussian elimination to write each system in triangular form
Feliz [49]

Answer:

To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

Step-by-step explanation:

Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:

  1. Swapping two rows
  2. Multiplying a row by a nonzero number
  3. Adding a multiple of one row to another row

To solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:

\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right]

For this matrix we need to perform the following row operations:

  • R_2 - 1 R_1 \rightarrow R_2 (multiply 1 row by 1 and subtract it from 2 row)
  • R_3 + 1 R_1 \rightarrow R_3 (multiply 1 row by 1 and add it to 3 row)
  • R_4 - 1 R_1 \rightarrow R_4 (multiply 1 row by 1 and subtract it from 4 row)
  • R_2 \leftrightarrow R_3 (interchange the 2 and 3 rows)
  • R_2 / 2 \rightarrow R_2 (divide the 2 row by 2)
  • R_1 - 1 R_2 \rightarrow R_1 (multiply 2 row by 1 and subtract it from 1 row)
  • R_4 - 1 R_2 \rightarrow R_4 (multiply 2 row by 1 and subtract it from 4 row)
  • R_3 \cdot ( -1) \rightarrow R_3 (multiply the 3 row by -1)
  • R_2 - 1 R_3 \rightarrow R_2 (multiply 3 row by 1 and subtract it from 2 row)
  • R_4 + 3 R_3 \rightarrow R_4 (multiply 3 row by 3 and add it to 4 row)
  • R_4 / 4.5 \rightarrow R_4 (divide the 4 row by 4.5)

After this step, the system has an upper triangular form

The triangular matrix looks like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5  \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 &  2 \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

If you later perform the following operations you can find the solution to the system.

  • R_1 + 0.5 R_4 \rightarrow R_1 (multiply 4 row by 0.5 and add it to 1 row)
  • R_2 + 0.5 R_4 \rightarrow R_2 (multiply 4 row by 0.5 and add it to 2 row)
  • R_3 - 2 R_4 \rightarrow R_3(multiply 4 row by 2 and subtract it from 3 row)

After this operations, the matrix should look like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9}  \\0 & 1 & 0 & 0 &   -\frac{1}{9}\\0 & 0 & 1 & 0 &  \frac{4}{9} \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

Thus, the solution is:

x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

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You gave your friend a short term 1.5 year loan of $30,000 at 2% compounded annually.
ElenaW [278]

Answer: $30,904.49

Step-by-step explanation:

I’m not sure if I did this right but it was the same was as the other question

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A recipe calls for 7 tbsp of oil how many fluid ounces of oil do you need
Readme [11.4K]

Answer:

3.5 fluid ounces

Step-by-step explanation:

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3 years ago
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PLZ HELP ME!<br> Directions up above the picture<br> **MATH (Algebra)
Vikentia [17]

Answer:

The answer to your question is t = 1.3 s

Step-by-step explanation:

Data

Equation    h(t) = -4.9t² + v₀t + h₀

v₀ = 0 m/s

h₀ = 8 m

t = ?

h = 0 m

Process

1.- Substitute the values in the formula

                  0 = -4.9t² + 0t + 8

2.- Simplification

                  0 = -4.9t² + 8

3.- Solve for t

                 4.9t² = 8

                      t² = 8/4.9

                      t² = 1.63

4.- Result

                      t = 1.27 ≈ 1.3 s

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3 years ago
Tom knows that in his school 10out of every 85 students are lefthanded. There are 391 students in Toms school. How many studentd
kompoz [17]
There are 39 left handed students at Toms school
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