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Lubov Fominskaja [6]
3 years ago
9

1) 2a × 2b 2) 3a × 2b × 2a 3) 2a × 4b × b 4) 3b × 2a × b 5) 3a × 2b × 2c 6) 2a × 3b × b × c 7) a × 4b × 2a × 2c 8) 3a × 3b × 3c

Mathematics
1 answer:
podryga [215]3 years ago
6 0

Step-by-step explanation:

1) = 4ab

2) 12a2b

3) 8ab2

4) 6ab2

5) 12abc

6) 6ab2c

7) 16a2bc

8) 27abc

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