Subtract the quotient of 15 divided 3 from the sum of 33 and 7

Mathematics

2 answers:

-BARSIC- [3]3 years ago

8 0

15/3 = 5

33+7 = 40

40 - 5 = 35

sattari [20]3 years ago

8 0

Hello there!

To start, first set up an expression in order to represent this problem:
(33+7)-(15÷3)

Now, simplify as according to the order of operations, or PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction):
(33+7)-(15÷3)
(40)-(15÷3)
(40)-(5)
40-5=35

Therefore, your final answer would be 35.

Hope this helps! :)

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A public health official is planning for the supplyof influenza vaccine needed for the upcoming flu season. She wants to estimat

Marizza181 [45]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25$

And rounded up we have that n=421

Step-by-step explanation:

We know that the sample proportion have the following distribution:

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We assume that a prior estimation for p would be $\hat p =0.5$ since we don't have any other info provided. And replacing into equation (b) the values from part a we got: