Option D
There are 15 dimes and 5 nickels
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "n" be the number of nickels
We know that,
Value of 1 dime = $ 0.10
Value of 1 nickel = $ 0.05
<em><u>There are three times more dimes than nickels</u></em>
Therefore,
Number of dimes = 3(number of nickels)
d = 3n ---------- eqn 1
<em><u>The total value is $ 1.75</u></em>
<em><u>Therefore, we frame a equation as:</u></em>
Number of dimes x Value of 1 dime + number of nickels x Value of 1 nickel = 1.75
0.10d + 0.05n = 1.75 -------- eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.10(3n) + 0.05n = 1.75
0.3n + 0.05n = 1.75
0.35n = 1.75
<h3>n = 5</h3>
<em><u>Substitute n = 5 in eqn 1</u></em>
d = 5(3)
<h3>d = 15</h3>
Thus there are 15 dimes and 5 nickels