Answer:
answer is 64
Step-by-step explanation:
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Write properties of function:
x intercept/zero: t₁ = -1, multiplicity 1; t₂ = 10 , multiplicity 1
vertex form: g (t) = (t - 9/2)² - 121/4
vertex: (9/2, -121/4)
![\sf\dfrac{3}{11}-(-\dfrac{6}{11})](https://tex.z-dn.net/?f=%5Csf%5Cdfrac%7B3%7D%7B11%7D-%28-%5Cdfrac%7B6%7D%7B11%7D%29)
Two negatives equals a positive:
![\sf\dfrac{3}{11}+\dfrac{6}{11}](https://tex.z-dn.net/?f=%5Csf%5Cdfrac%7B3%7D%7B11%7D%2B%5Cdfrac%7B6%7D%7B11%7D)
Add the numerators and keep the denominator:
Answer:
The probability of 1 or less children from that group to learn how to swim before 6 years of age is 0.072
Step-by-step explanation:
In this case we need to compute the probability of none of these 12 children learns to swim before 6 years of age. This is given by:
p(0) = (1 - 0.312)^(12) = 0.688^(12) = 0.01124
We now need to calculate the probability that one child learns to swim before 6 years of age.
p(1) = 12*0.312*(1 - 0.312)^(11) = 3.744*(0.688)^(11)
p(1) = 3.744*0.01634
p(1) = 0.0612
The probability of 1 or less children from that group to learn how to swim before 6 years of age is:
p = p(0) + p(1) = 0.01124 + 0.0612 = 0.07244