Step-by-step explanation:
with your square root symbol I never know what is inside the square root and what is possibly outside.
so, I can only guess and see what comes close.
f(x) = 2x² + x - 1
g(x) = sqrt(2x - 1) ??? is that so ?
h(x) = -2
2g(f(x)) + h(x)
g(f(x)) means that the whole f(x) expression is used as x in g(x).
the whole combined function is then
2×sqrt(2(2x² + x - 1) - 1) - 2
2×sqrt(4x² + 2x - 2 - 1) - 2
2×sqrt(4x² + 2x - 3) - 2
and if I am not mistaken, then this is the solution you mentioned at the beginning (if I try to read between the typos and missing info).
this is how people get to this.
do you understand it now ? or is there still something unclear ?
Less than 6km.............................................
The answer is.................
A!!!!!!!!!!!!
Answer:
y= 3x -4
Step-by-step explanation:
The equation of a line can be written in the form of y=mx +c, where m is the slope and c is the y-intercept. This is also known as the slope-intercept form.

Since the given equation is in the slope-intercept form, we can identify its slope from the coefficient of x.
Slope= -⅓
The product of the slopes of perpendicular lines is -1.
Slope of perpendicular line


= 3
Thus, the equation of the perpendicular line is given by:
y= 3x +c
Substitute a pair of coordinates that the line passes through to find the value of c.
When x= 3, y= 5,
5= 3(3) +c
5= 9 +c
<em>Minus 9 on both sides:</em>
c= 5 -9
c= -4
Hence, the equation of the perpendicular line is y= 3x -4.
Additional:
For more questions on equation of perpendicular lines, do check out the following!
Answer and Step-by-step explanation:
C1) (x-1)²+(y+2)²=1 C1 (1,-2) R1 = √1 = 1
C2) (x+5)²+(y-4)²=4 C2 (-5,4) R2 = √4 = 2
DISTANCE FORMULA: d² = (y₂-y₁)²+(x₁-x₂)²
calculating the distances between the 2 center:
d² = (4-(-2))²+(-5-1)² = (6)²+(-6)² = 36 + 36 = 72 ⇒ d = √72
√72 ≈ 8.49
R1 = 1 and R2 = 2
If the circles were secants, d would be < than R1 + R2.
If the circles were tangent, d would be = to R1 + R2
As d > than R1 + R2, we know that the circles do not intercept.