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3 years ago

2x - 3y = 8 // Find y

Mathematics

1 answer:

konstantin123 [22]3 years ago

7 0

Answer:

$y = -\frac{2}{3} x - \frac{8}{3}$

Step-by-step explanation:

$2x - 3y = 8\\$

Isolate y

$-3y = 8-2x\\-3y = -2x+8$

Divide both sides of the equation by -3

$\frac{-3y}{-3} = \frac{2x}{-3} +\frac{8}{-3} \\\\y = -\frac{2}{3} x - \frac{8}{3}$

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Each course at a community college is worth 1 or 2 credits. A group of students is taking a total of 16 courses that are worth a

Anuta_ua [19.1K]

Answer:

They are taking 12 2 credit courses

The are taking 4 1 credit courses

Step-by-step explanation:

x = 1 credit courses

y = 2 credit courses

The number of courses is 16

x+y = 16

The number of credits is 28 so multiply the course by the number of credits

1x+2y=28

Subtract the first equation from the second equation

x+2y =28

-x-y=-16

-----------------

y = 12

They are taking 12 2 credit courses

We still need to find the 1 credit courses

x+y = 16

x+12= 16

Subtract 12 from each side

x-12-12 = 16-12

x =4

The are taking 4 1 credit courses

6 0

3 years ago

Helppppppp mathhhhhhhh

aivan3 [116]

Again using the Pythagorean Theorem:

h^2=x^2+y^2, where h is the hypotenuse of a right triangle and x and y are the side lengths. You are given that the hypotenuse is 34 ft and the base side is 16ft. Let h=34, x=16, and y=height, then you have:

34^2=16^2+y^2

y^2=34^2-16^2

y^2=1156-256

y^2=900

y=√900

y=30 ft

So the ladder will reach a spot 30 feet high on the building.

8 0

3 years ago

How much is 80% from 250.00

rodikova [14]

If you need further help on how they got the answer, this equation will take more time, but it will also help you understand these types of problems. Part÷Whole=Percent÷100
Part= X because it is what you are trying to find.
Whole=250 because it is what you are taking the percentage of.
Percent=80
Now you have:
X÷250=80÷100
Set this up in fraction form and cross multiply.
You get:
100x=250×80
250×80=20,000
100x=20,000
X=200

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2 years ago

Read 2 more answers

‪YALL TEXT +1 (201) 496-1249 TO STOP BEING RACIST‬

ArbitrLikvidat [17]

Answer:

bet I will

Step-by-step explanation:

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3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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3 years ago