Answer:
a). Mileage for carA= 
, and mileage for carB=
b).total mileage for both is similar to average of them= 
=![\frac{5x+4}{2x(x+1)}[tex]mil/gal](https://tex.z-dn.net/?f=%5Cfrac%7B5x%2B4%7D%7B2x%28x%2B1%29%7D%5Btex%5Dmil%2Fgal)
Step-by-step explanation:
It is given that the distance traveled by car 
And distance traveled by car 
We know the mileage is mile/gallon,
a).So mileage of car 
Similarly , the mileage for car 
b).total mileage for both is similar to average of them=
Now divide by 2 for total(average) mileage.
.
Thus those are the answers.
Looking at this in terms of sets, let's call O the set of all owls, and F the set of all things that can fly. What this original statement is saying every animal that's a member of the set of all owls is also a member of the set of all things that can fly, or in other words, O⊂F (O is a subset of F). Negating this tells us that, while there's <em>at least one</em> element of O that also belongs to F, O is not contained entirely in F (O⊆F, in notation), so a good negation or our original statement might be:
<em>Not all owls can fly.</em>
