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lions [1.4K]
3 years ago
11

Evaluate gh-k when g = -8 ,h=4 and k =-2 Please help

Mathematics
2 answers:
Ainat [17]3 years ago
8 0

Here is your answer:

In order to solve this equation you need to replace the variables with the numbers then solve using order of operations.

  • gh-k
  • -8\times4--2
  • Following the rules of PEMDAS:
  • -8 \times 4 = -32
  • -32 - -2
  • Use KCC:
  • -32 - -2 = -32 + 2
  • -32 + 2 = -30
  • =-30

Therefore your answer is "-30."

Hope this helps!

navik [9.2K]3 years ago
6 0

g h - k

= -8 * 4 - (-2)

= -32 + 2

= -30  answer

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KATRIN_1 [288]

Answer:

1) 75 copies were sold

2)expected wage=720

Step-by-step explanation:

in this equation, y represents wages and x represents number of copies sold

lets take the trendline, y=6x+120

since the amount earnt is $570, we can take this to be our y variable

570=6x+120

450=6x

x=75

1) 75 copies r sold

2) this time we substitue the 100 for x

y=6(100)+120

y=600+120

y=720

2) expected wage=720

4 0
3 years ago
Consider this quadratic equation. 2x2 − 1 = 3x + 4 Which equation correctly applies the quadratic formula?
Mariulka [41]

Answer:

\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)}

Step-by-step explanation:

Quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

2x^2-1=3x+4\\\\2x^2-3x-5=0\\\\\\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)} \\\frac{3+-\sqrt{9+40} }{4}

x = \frac{3+-7}{4}

Hope this helps and God bless!

6 0
3 years ago
a quantity with an initial value of 5900 decays exponentially at a rate of 0.85% every 7 years. what is the value of the quantit
laila [671]

The value of the quantity after 99 months is 5228.58.

Given that,  an initial value = 5900, rate of decay = 0.85% and time period = 7 years.

<h3>What is the exponential decay?</h3>

The quantity decreases slowly after which the rate of change and the rate of growth decreases over a period of time rapidly. This decrease in growth is calculated by using the exponential decay formula.

The exponential decay formula formula is Amount=Initial\ value(1-\frac{r}{100} )^{\frac{t}{n} }

Here, the value =5900(1-\frac{0.85}{100} )^{\frac{99}{7} }

= 5900×(0.9915)^{14.14}

= 5900×0.8862

= 5228.58

Therefore, the value of the quantity after 99 months is 5228.58.

Learn more about the exponential decay here:

brainly.com/question/13674608.

#SPJ1

4 0
1 year ago
Select all the factor pairs. What are the factor pairs of -144 that add to 0.
Yanka [14]
-12 and 12 are the aswer
7 0
3 years ago
How do you solve for the segment area in a circle?
Aleks04 [339]
The area of the entire sector of DEF = 60 / 360 * PI * radius^2
sector area = 1 / 6 * 3.14159265... * 20^2
sector area = <span> <span> <span> 209.4395102393 </span> </span> </span>

segment area = sector area - triangle DEF Area
triangle DEF Area = (1/2) * 20 * sine 60 * 20
triangle DEF Area = (1/2) * 0.86603 * 400
triangle DEF Area = <span><span><span>(1/2) * 346.412 </span> </span> </span>
triangle DEF Area = <span> <span> <span> 173.206 </span> </span> </span>

segment area = <span> <span> 209.4395102393 </span> -173.206
</span>
segment area = <span> <span> <span> 36.2335102393 </span> </span> </span>
segment area = 36.23 m

Source:
http://www.1728.org/circsect.htm



6 0
3 years ago
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