What is the equation of a line that is parallel to −3x+4y=4 and passes through the point (4, 0) ?
1 answer:
First, change the given equation to slope-intercept form:
4y = 3x + 4
y = (3/4)x + 1
Because the line we are trying to write the equation for is parallel to the above line, the new line must have the same slope (3/4).
We can then substitute (4, 0) to find the y-intercept (b):
0 = (3/4) * 4 + b
0 = 3 + b
-3 = b
Our y-intercept is -3
We can now write the whole equation:
y = (3/4)x - 3
Your final answer is y = (3/4)x - 3
Hope this helps!! Let me know if you have ANY questions.
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