Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
Answer:
A & B
Step-by-step explanation:
A is spot-on because of the use of distributive property. B by the use of like terms.
Answer:
3.95 and -3.95
Step-by-step explanation:
To graph a circle you can use the formula or (x – h)^2 + (y – k)^2 = r^2. So substituting in the given, we get x^2+y^2=49/pi. The x intercept is when y=0. So x^2=49/pi and so
x = sqrt(49/pi) and rounding to the nearest tenth, we get 3.95 and -3.95 because it isn’t a principal square root.
Answer is A and B
A) -7.13 < -0.8
B) -0.86 < -0.8
C) -0.79 > -0.8
D) 0.846 > -0.8
Answer:
The inverse is 1/2x -3/2
Step-by-step explanation:
y =2x+3
Exchange x and y
x = 2y+3
Solve for y, subtracting 3 from each side
x-3 = 2y+3-3
x-3 =2y
Divide each side by 2
(x-3)/2 = 2y/2
1/2x - 3/2 =y
The inverse is 1/2x -3/2
