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2 years ago

My math problem dealing with fractions ask What is 1/8 of 9?

Mathematics

2 answers:

Zina [86]2 years ago

5 0

Answer:

1 1/8

Step-by-step explanation:

1/8 of 9

Of means multiplication

1/8 x 9

= 9/8

= 1 1/8

Norma-Jean [14]2 years ago

3 0

Answer:

Step-by-step explanation:

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Mary has 2 more video games than John. Together, they have 30 video games.

k0ka [10]

Answer: Mary has 16 video games.

Step-by-step explanation:

x+(x+2) =30

2x + 2 =30

-2 -2

2x =28

x= 14

(14+ 2) = 16

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3 years ago

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Brenda had bowling scores of 92, 110, 85, 78, and 96. She completed the steps below to determine the score she needs in her next

Yakvenalex [24]

Answer:

<u>Hence final answer is B: Step 2.</u>

Step-by-step explanation:

Step 1: Find the total points needed to score in six games: 96x6=576

Justification:

Product of 96 and 6 is 576 which is same number found by Brenda. So step 1 is correct.

Step 2: Find the total points scored: 92+110+85+78=365

Justification:

Sum of total points scored by Brenda is 92+110+85+78= 461.

But she got different value 365.

Hence step 2 is wrong.

<u>Hence final answer is B: Step 2.</u>

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2 years ago

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PLZ NEED HELP ASAP!!!

madam [21]

Answer:

C and D

Step-by-step explanation:

I had this same problem on my quiz

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2 years ago

The table below shows the relationship between the buses in the school parking lot and and the number of students on them. What

lawyer [7]

Answer:

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Step-by-step explanation:

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2 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

2 years ago