78! is the answer to this question! trust! -6
Answer:
PLEASE HELP ME WILL MARK BRAINLIEST
Step-by-step explanation:

Here we go ~
In the above question, it is given that :

A.) Find f(2) :


or

B.) Find
:

so, we can write it as :



Now, put x =
, and y = x and we will get our required inverse function ~

C.) Find
:



Answer:
a) For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Answer:
B. p+121 is ≤ 345
Step-by-step explanation:
Talula can't go over the amount of 345 because it would go over the limit therefore the less than or equal to sign is needed. It would be p PLUS 121 because it would be a number less than or equal to 345 and p is the variable that is has to be less than or equal to 345.