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Simora [160]
3 years ago
10

After dillion deposited his money,he bought an $8 comic book with the money that was left. The sales tax was 7%.How much money d

id Dillion have left after his deposit and purchase. SHOW ALL WORK
(Dillion deposited 46.50)
Mathematics
2 answers:
PIT_PIT [208]3 years ago
5 0
46.5=8(1.07)
that's all the work you need. 37.94 i belief
otez555 [7]3 years ago
5 0
X= amount left after deposit & purchase

x= $ deposit - [$ book * (1 + sales tax)]
x= 46.50 - [8 * (1 + 7%)]
x= 46.59 - (8 * 1.07)
x= 46.50 - 8.56
x= $37.94 amount left

Hope this helps! :)
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What is the value of c in the equation below? 2^-4(2^2)=a^b=c
Triss [41]

Answer:

The answer is option 4.

Step-by-step explanation:

You have to use Indices Law,

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

{a}^{ - n}  =  \frac{1}{ {a}^{n} }

So for this question :

{2}^{ - 4}  \times  {2}^{2}

=  {2}^{ - 4 + 2}

=  {2}^{ - 2}

{a}^{b}  = c \\ c =  {2}^{ - 2}

c =  \frac{1}{ {2}^{2} }

c =  \frac{1}{4}

5 0
3 years ago
To find 19+(11+37), lennie added 19 and 11. then he added 37 to the sum. what property did he use?
Rudiy27
<span>Lennie used associative law of addition.
Associative law of addition doesn’t matter how you group the given numbers to add.

a + (b + c) = (a + b) + c
=> 19 + (11 + 37) or ( 19 + 11) + 37
=>  19 + (48) or (30) + 37
=> 67 or 67</span>



3 0
3 years ago
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mylen [45]
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Solve (x-3)^2=5 plssss <br> thxs
Andreyy89

Answer:

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Step-by-step explanation:

7 0
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Hi. I need help with these questions (see image)<br>Please show workings.<br>​
pantera1 [17]

Answer:

see explanation

Step-by-step explanation:

Using the chain rule

Given

y = f(g(x)), then

\frac{dy}{dx} = f'(g(x))  × g'(x) ← chain rule

and the standard derivatives

\frac{d}{dx} (log_{a} x ) = \frac{1}{xlna} , \frac{d}{dx}(lnx) = \frac{1}{x}

(a)

Given

y = log_{a}\sqrt{(1+x)}

\frac{dy}{dx} = \frac{1}{lna\sqrt{(1+x)} } × \frac{d}{dx} ((1+x)^{\frac{1}{2} }

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   = \frac{1}{lna\sqrt{(1+x)} } × \frac{1}{2\sqrt{(1+x)} } × 1

   = \frac{1}{2lna(1+x)}

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(b)

Given

y = ln sinx

\frac{dy}{dx} = \frac{1}{sinx} × \frac{d}{dx}(sinx)

   = \frac{1}{sinx} × cosx

   = \frac{cosx}{sinx}

   = cotx

5 0
3 years ago
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