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mixas84 [53]
2 years ago
12

Hi. I need help with these questions (see image)Please show workings.​

Mathematics
1 answer:
pantera1 [17]2 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

Using the chain rule

Given

y = f(g(x)), then

\frac{dy}{dx} = f'(g(x))  × g'(x) ← chain rule

and the standard derivatives

\frac{d}{dx} (log_{a} x ) = \frac{1}{xlna} , \frac{d}{dx}(lnx) = \frac{1}{x}

(a)

Given

y = log_{a}\sqrt{(1+x)}

\frac{dy}{dx} = \frac{1}{lna\sqrt{(1+x)} } × \frac{d}{dx} ((1+x)^{\frac{1}{2} }

   = \frac{1}{lna\sqrt{(1+x)} } × \frac{1}{2} (1+x)^{-\frac{1}{2} } × \frac{d}{dx} (1 + x)

   = \frac{1}{lna\sqrt{(1+x)} } × \frac{1}{2\sqrt{(1+x)} } × 1

   = \frac{1}{2lna(1+x)}

   = \frac{1}{(1+x)lna^2}

(b)

Given

y = ln sinx

\frac{dy}{dx} = \frac{1}{sinx} × \frac{d}{dx}(sinx)

   = \frac{1}{sinx} × cosx

   = \frac{cosx}{sinx}

   = cotx

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The h.w. grant corporation used regression analysis to predict the annual cost of indirect materials. the results were as​ follo
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Indirect material cost: y
explained by units produced: x
Linear regression. Cost estimation equation: y=mx+b
Constant: b=$15,640
Standard error of y estimate=$3,600
r^2=0.7704
Number of observations: n=22
x coeffient: m=11.25
Standard error of x coefficient=2.19

m=11.25, b=15,640 → y=11.25x+15,640

Answer: The cost estimation equation is y=11.25x+15,640
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1 year ago
Sienna planned a rectangular pool, as shown in the scale drawing below.
svlad2 [7]

Answer:

The scale factor is

27.5 feet / 22 feet = 1.25.

Explanation:

Whenever you are calculating factors, you are comparing two measurements. In this problem we compared a longer length to a shorter length pool. The length was changed to (27.5 feet) and youre comparing to the length it was originally (22 feet).

Ok so you know the two measurements being compared, but how come it’s 27.5/22 and not 22/27.5? Because the value got bigger.

In this problem you had a pool with long side of 22 ft. But then you made it longer to 27.5 ft. So it scales up,

It went from 100% its length to 125% its length. So the length is 125% / 100% = 1.25 times longer than it used to be.

Here’s another example:

How do you calculate your grade percentage on a test? You take the amount of points you earned and divide by the total possible points. Your grade percentage is a comparison of your score (Compare value) compared to a perfect score (reference value) .

So lets say your test had 22 total points. You get all the answers correct so you get 22/22 points which is 22/22*100 = 100%. Let’s say you get an extra bonus question correct so you end up with even more points and you get 27.5 points out of 22. By getting the bonus points you scaled up your score! Now your score is 27.5/22 * 100 = 125%. So you went from 100% to a 125%. Or from a scale factor of 1 to 1.25.

Whenever the value is getting bigger than it was, you’re going to have a compared percentage over 100%. If the value gets smaller, then you would get a compared percentage less than 100%. Similarly a factor scale is going to be over 1 if the compared value is getting bigger, and less than 1 if it’s getting smaller.

So you don’t need to use percentages, factors are the same they just look a little different.

27.5/22 = 125% / 100% = 1.25

In summary just do this division:

(compare value)/(reference value). The result is how big the top value is compared to the bottom value.

5 0
3 years ago
Read 2 more answers
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