Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
The answer is "88.9%"
Step-by-step explanation:
The Variance percentage indicates through the REgression equation but, the R-Square, it becoming the determination coefficient. 88.871% of the variance could be explained according to the above results.
Answer:
C
Step-by-step explanation:
Not integer, irrational
Answer:
4x + 1
Step-by-step explanation:
note that (f + g)(x) = f(x) + g(x) , thus
f(x) + g(x)
= x + 3x + 1 ← collect like terms
= 4x + 1
Answer:
1/5^9
Step-by-step explanation:
You keep the 5 the same
Then you subtract the exponents...
-6 - 3 = -9
Since it’s negative and you can’t have a negative exponent you have to put a 1 as the numerator. So...
1/5^9
