Find a polynomial function of lowest degree with rational coefficients that has the given numbers as some of its zeros.
1 answer:
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Answer:
Step-by-step explanation:
Question 2
As far as I can see, you got it right. The general transformation for 90 ccw is
(x,y) ===> (-y, x)
What that means is for the x you put in -y changing the sign to the opposite and for the y you put in x and this time you leave the sign alone . The transformation is shown in the left hand diagram.
The two tables are shown below.
Original
- (1,4)
- (1,2)
- (3,2)
- (3,5)
The transformed table is
- (-4,1)
- (-2,1)
- (-2,3)
- (-5,3)
- (-4,1) This is just to let the program know to close the figure For some reason this did not have lines and if I delete it and put the lines in, I won't be able to upload the new diagram.
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Four
This one transforms from (x,y) to (-x,-y) which means where you see an x, you put a - x and where you see a y, you put a minus y. It is the middle frame.
Original
- (-4,3)
- (0,3)
- (-2,0)
- (-4,3) Here again, this is just to close the figure.
The transformed figure in red I think is
- (4,-3)
- (0,-3
- (2,0)
- (4,-3) And this closes the figure as well.
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Six
The diagram is on the right
Reflection about the y axis. Here the transformation is (x,y) ====> (-x,y) notice the ys don't change.
- (-3,0)
- (-5,-2)
- (-1,-2)
There is no closure.
Reflection
- (3,0)
- (5,-2)
- (1,-2)
Answer:
Step-by-step explanation:
All you have to do is multiply 35 by 8 to get 280.
I am joyous to assist you anytime.