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3 years ago

Please help me with this

Mathematics

2 answers:

AfilCa [17]3 years ago

8 0

Answer:

A. 4/5

Step-by-step explanation:

The red dot is on 0.8

0.8 as a fraction is 4/5

TEA [102]3 years ago

4 0

The answer is 4/5 because between each number it is divided by 5. 4 out of 5 is 4/5.

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SOLVE FOR X 3x +5 = x -10 A. -5/4 B. -5 C. -15/2 D. -15 OA B. D

kifflom [539]

Hello!

$\large\boxed{\text{C.} \frac{-15}{2}}$

3x + 5 = x - 10

Solve for x by isolating the variable.

Subtract 5 from both sides:

3x + 5 - 5 = x - 10 - 5

3x = x - 15

Subtract x from both sides:

3x - x = x - x - 15

2x = -15

Divide both sides by 2:

2x /2 = -15 / 2

x = -15/2.

4 0

3 years ago

Read 2 more answers

Help pls I'm gonna be screwed if you don't get this pls pls pls anyone who knows math well pls help me I'm gonna cry it's over d

erica [24]

Answer:

WRONG ALL

Step-by-step explanation:

3. Should be:

$- 4 \frac{7}{8} \times \frac{2}{3} \\ \\ - \frac{39}{8} \times \frac{2}{3} \\ \\ \frac{ -13}{4}$

4. Should be:

$- 3 \frac{1}{5} + - \frac{2}{3} \\ \\ - 3 \frac{3}{15} - \frac{10}{15} \\ \\ - 3 \frac{7}{15}$

I hope this helps you :)

7 0

3 years ago

The number of kilograms of water in a human body varies directly as the mass of the body. A 93-kg person contains 62-kg of water

slava [35]

We know that the variation is proportianal, that is we can relate the quantities as:

$y=kx$

where y is the mass of the body and x is the mass of water. From the values given we have that:

$\begin{gathered} 93=62k \\ k=\frac{93}{62} \\ k=\frac{3}{2} \end{gathered}$

hence the constant of proportionality is 3/2. Now, if the mass of the water is 75, then the mass of the body is:

$\frac{3}{2}\cdot75=112.5$

Therefore, the mass of the body is 112.5 kilograms

4 0

1 year ago

Starting time2:00 pm Ending time 8:30 what was the elapsed time

Feliz [49]

The elapsed time was 6 hours and 30 minutes. Hope this helps.

7 0

3 years ago

Read 2 more answers

Maria drove to a business appointment at 50mph in the morning. Her average speed on the return trip in the afternoon was 40 mph.

MakcuM [25]

Answer:

Distance to appointment point = 5 miles

Step-by-step explanation:

Let s be the distance to the appointment point,

We have Maria drove to a business appointment at 50mph in the morning.

Time taken in the morning

$t_m=\frac{s}{50}=0.02s$

Her average speed on the return trip in the afternoon was 40 mph.

Time taken in the afternoon

$t_a=\frac{s}{40}=0.025s$

Given that the return trip took 1/4hr longer because of traffic.

That is

$t_a-t_m=\frac{1}{4}hr=0.025hr$

Substituting

$t_a-t_m=0.025hr\\\\0.025s-0.02s=0.025\\\\s=5miles$

Distance to appointment point = 5 miles

7 0

3 years ago

Please help me with this​

Please help me with this