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Zigmanuir [339]
3 years ago
8

How do you round to the nearest cent

Mathematics
1 answer:
Allisa [31]3 years ago
3 0

See the explanation

<h2>Explanation:</h2>

Rounding to the nearest cent is the same as rounding to the nearest hundredth. In order to round this way, you must use the thousandths place so that you can know whether hundredths place rounds up or stays the same.

So the rules is as follows:

  • If the thousandths place is 5 or above, we add 1 to the digit of the hundredths place.

For example:

0.64<u>8</u>3

4: It's in the hundredths place

<u>8</u>: It's in the thousandths place

8 is greater than 5, so we round it as:

0.65

  • If the thousandths place 4 or below, the digit in the hundredths place stays the same.

18.9<u>2</u>3569

9: It's in the hundredths place

<u>2</u>: It's in the thousandths place

2 is less than 5, so we round it as:

18.92

<h2>Learn more:</h2>

Rounding to tens place: brainly.com/question/109166

#LearnWithBrainly

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How do I find the surface area and volume of the larger figure using that of the smaller figure?
dalvyx [7]
We know that
scale factor=1/8

volume smaller figure=[scale factor]³*volume larger figure
so
volume larger figure=volume smaller figure/[scale factor]³
volume smaller figure=7 km³
volume larger figure=7/[1/8]³----> 7/(1/512)---> 7*512---> 3584 km³

the answer Part a) is 
the volume of the larger figure is 3584 km³

surface area smaller figure=[scale factor]²*surface area larger figure
surface area larger figure=surface area smaller figure/[scale factor]²
surface area smaller figure=9 km²
surface area larger figure=9/[1/8]²----> 9/(1/64)---> 9*64---> 576 km²

the answer part b) is
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4 0
3 years ago
(cos x - (sqrt 2)/2)(sec x -1)=0
Darya [45]

(\cos x-\frac{\sqrt{2}}{2})(\sec x-1)=0 [/tex]

=(\cos x-\frac{1}{\sqrt{2}})(\sec x-1)=0 [/tex]

\frac{(\sqrt{2}\cos x-1)}{\sqrt{2}}(\frac{1}{\cos x\ }-1)=0

(Reciprocal Identity)

(\frac{^{\sqrt{2}\\cos  x-1}}{^{\sqrt{2}}})(\frac{1-\cos x}{\cos x})=0

\frac{^{(\sqrt{2}\cos x-1})}{\sqrt{2}}\frac{(1-\cos x)}{\cos x}=0

(\sqrt{2}\cos x-1}){(1-\cos x)}=0 (ZeroProduct Property)

\sqrt{2}\cos x-1=0

\sqrt{2}\cos x=1

\cos x=\frac{1}{\sqrt{2}}

x=\frac{\Pi }{4}

and

1-\cos x=0

\cos x=1

x=0

x=0 and x=\frac{\Pi }{4} are the solutions.

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Brainliest if correct
dybincka [34]

Answer:

-2

Step-by-step explanation:

4 0
2 years ago
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