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Vadim26 [7]
3 years ago
7

anne marie needs to rent a car for 9 days to take on vacation. The cost of renting a car is $66 per day, $15.99 for insurance, a

nd $42.50 to fill up the gas tank. Find the total cost of her rental car. Make a table

Mathematics
2 answers:
cluponka [151]3 years ago
7 0
I myself also got 652.49 and the only table that I thought of making was as the picture shows hoped it helped?

Licemer1 [7]3 years ago
6 0
$652.49 I got this answer by jotting it down and solving it. It was quite simple. But sorry if I sound conceited.
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What is the ratio for the surface areas of the rectangular prisms shown below, given that they are similar and that the ratio of
Harrizon [31]

Answer:

9 : 1

Step-by-step explanation:

given a linear ratio = a : b, then the corresponding area ratio is

a² : b²

Here the linear ratio of their edges = 3 : 1, hence

ratio of surface areas = 3² : 1² = 9 : 1


4 0
3 years ago
Find the sine of both angle A and angle B.
olchik [2.2K]
Sin = opposite/hyp

Sin A = 10/26   = 5/13

Sin b = 24/26 = 12/13

The answer is option A

Hope this helps



6 0
3 years ago
Read 2 more answers
12 2/5 - 4 4/6 in whole numbers & fractions
Artist 52 [7]
12 2/5 - 4 4/6 = ?
Whole number: It cannot be a whole number, since it is a repeating decimal. As a repeating decimal, it is 7.7333333333333 and so on. If you round it to the ones place, it would become 8. As a simplified decimal, it would be 7.7

Fraction: 7 11/15

HOPE THIS HELPED. ;-)
6 0
3 years ago
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
3 years ago
How should I solve this? I tried to but I couldn't get past the quadratic formula.
xxMikexx [17]
First multiply all terms by z
8-z^2=4z

Then order into standard form
-z^2-4z+8=0

Multiply the equation by -1
z^2+4z-8=0

Plug into quadratic equation
-4±√16-4(-8)
-4±√48

(-4±4√3)/2
-2±2√3

Final answer: z=-2± 2√3
8 0
3 years ago
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