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Marizza181 [45]
3 years ago
9

56 successful students is 70​% of what number of​ students?

Mathematics
2 answers:
ivanzaharov [21]3 years ago
4 0

Answer:

56 is 70% of 80 students.

Step-by-step explanation:

70% = 0.7

56 divided by 0.7 = 80

Fofino [41]3 years ago
4 0

[ Answer ]

\boxed{80}

[ Explanation ]

56 is 70% of __

Turn 70% into a decimal

70% is out of 100, so our fraction (which also means division) would look like this:

\frac{70}{10} = 70 ÷ 100

70 ÷ 200 = 0.7

Now, divide

56 ÷ 0.7

= 80

56 is 70% of 80

\boxed{[ \ Eclipsed \ ]}}

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hichkok12 [17]
Y=6X+9 the A is #1                                              
all you need to do is simp the equation 
4 0
3 years ago
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Rewrite the function by completing the square<br><br> h(x)=4x^2+4x+1
lisov135 [29]

Answer:

h(x) = 4(x+\frac{1}{2})^{2}

Step-by-step explanation:

h(x)=4x^2+4x+1\\h(x)=4(x^2+x+\frac{1}{4}) \\h(x)=4(x^2+x+\frac{1}{4})\\h(x) = 4(x+\frac{1}{2})^{2}

8 0
3 years ago
Find the x-intercepts for the parabola defined by the equation below. y = x2 + 9x + 14
faltersainse [42]

Answer:

x - intercepts are (-7,0) and (-2,0)

A is the correct option.

Step-by-step explanation:

We have been given the equation of the parabola y=x^2+9x+14

For x- intercept, y = 0

0=x^2+9x+14

We can split the middle term as 9x = 7x +2x

x^2+7x+2x+14=0

Now take GCF

x(x+7)+2(x+7)=0

Factored out the common term

(x+7)(x+2)=0

Apply the zero product property

(x+7)=0,(x+2)=0

Solve for x

x=-7,-2

Hence, x - intercepts are (-7,0) and (-2,0)

A is the correct option.

4 0
3 years ago
Write 28/20 and 70/50 as fractions in simplest form. then determine whether the ratios form a proportion.
jeyben [28]
28/20 in simplest form is: 7/5
70/50 in simplest form is 5/7
Because,
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5 0
3 years ago
Need urgent help in mathematics!! Will mark brainliest!!!!
sesenic [268]

Hey there!!

How do we solve this problem :

We will use the combinations formula to solve this :

c ( n , r ) where n = 11 and r = 2

c ( n , r ) =  n ! / r ! ( n - r ) !

... 11 ! / 2 ! ( 11 - 2 ) !

... 11! / 2! × 9!

... 11! / 2 × 9!

... 11×10×9×8×7×6×5×4×3×2 / 2×9×8×7×6×5×4×3×2

... 11×10 / 2

... 11 × 5

... 55 combinations.

Hence, the required answer = 55 , option ( d )

Hope my answer helps!

8 0
3 years ago
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