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3 years ago

If we consider the toss of four coins as an experiment, how many equally likely outcomes does the sample space have?

1 answer:

6 0

There are 16 possible outcomes.

This is found by taking the number of possible outcomes for each toss, 2, and raising it to the 4th power (for 4 tosses):

2⁴ = 2*2*2*2 = 16

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What is the image point of (-1,1) after a translation left 2 units and<br> down 2 units?

AveGali [126]

Answer:

The new point is (-3,-1)

Step-by-step explanation:

yessir

3 0

2 years ago

Kevin is observing the population of the fish he put into a pond. He built a pond and populated it with 500 fish. The population

laila [671]

Here we will use exponential form, which is

$y = y_{0} e^{kt}$

Initial value, y0 = 500

Double of 500 = 1000

$1000 = 500e^{k*1}$

$2 = e^k$

$k= ln (2)$

Required equation is

$y=500e^{x ln2} \\ y= 500 (2)^x$

6 0

3 years ago

A population of rabbits doubles evey 4 months. if the population starts out with 8 rabbits how many rabbits will there be in 1 y

Arlecino [84]

Well. You start with two rabbits, and it triples every month, so:

0 months: 2 rabbits.
1 month: 2*3 = 6 rabbits.
2 months: 6*3 = 18 rabbits.
3 months: 18*3 = 54 rabbits.

4 0

2 years ago

Sandals and flip-flops on sale at the store! Janet purchased 3 pairs of sandals and 1 pair of flip-flops for $23.50, while Micha

Lerok [7]

Answer:

1 sandal= $7

1 flip flop =$2.5

Step-by-step explanation:

say one sandal costs x and one flip flop costs y

3 x+y=23.50

4x+2y=33

solve using simultaneous equationsto find the values of x and y

3 0

2 years ago

The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal

Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The other parameters are given as follows:

$\overline{x} = 111000, \sigma = 36730, n = 36$

Hence, the lower bound of the interval is:

$\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002$

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

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8 0

1 year ago