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Nataly_w [17]
4 years ago
5

car traveled 576 mi averaging a certain speed. If the car had gone 8 mph​ faster, the trip would have taken 1 hour less. Find th

e average speed.
Mathematics
1 answer:
Zepler [3.9K]4 years ago
6 0

Answer:64mi/hour

Step-by-step explanation:

V=speed × time

V=s×t .....equation (1)

v=576

for taking one hour: t-1

speed is: s+8

From equation(1)

V=(s+8)(t-1)

(s+8)(t-1)=576

Expand the bracket

st-s+8t-8=576

Substitute the value of st which is 576

576-s+8t-8=576

Collect the like terms

-s+8t-8=0

s=8t-8

Subtitude into the value of s

576= (8t-8)×t

576=8t^2-8t

8t^2-8t=576

8t^2-8t-576=0 (divide both by 8)

t^2-t-72=0

By factorization method

Product is (-9 and 8)

(t-9)(t+8)=0

t=9 or t=-8

V=s×t

576=s×9

9s=576

s=576/9

s=64mi/hour

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Which of the following statements are true?
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Answer: D (I think)

Step-by-step explanation:

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Question: find the value of x.<br><br><br> CAN someone please help me please explain!!
ELEN [110]

Step-by-step explanation:

Sum of interior angles of a polygon is given by (n-2)180°

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Since this polygon has 5sides,

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4 years ago
Triangle ABC is reflected across the line y=2x to map onto triangle RST. Select all statements that are true.
Anettt [7]

The reflection transformation in the question is a rigid transformation,

therefore, the image and the preimage are congruent.

The statements that are true are;

  • <u>AB = RS</u>
  • <u>∠ABC ~ ∠RST</u>
  • <u>ΔABC = ΔRST</u>
  • <u>m∠BAC = m∠SRT</u>

Reasons:

The given parameter are;

Triangle ΔABC is reflected across the line 2·X, to map onto triangle ΔRST

Required:

To select the true statements

Solution:

A reflection is a rigid transformation, therefore, the distance between corresponding points on the image and the preimage are equal.

Therefore;

AB = RS

BC = ST

AC = RT

Given that the image formed by a reflection is congruent to the preimage, we have;

ΔABC ≅ ΔRST

∠ABC ≅ ∠RST

m∠ABC = m∠RST by the definition of congruency

∠BCA ≅ ∠STR

m∠BCA = m∠STR by the definition of congruency

∠BAC ≅ ∠SRT

m∠BAC = m∠SRT by the definition of congruency

Therefore, the true statements are;

  • <u>AB = RS</u>; Image formed by rigid transformation
  • <u>∠ABC ~ ∠RST</u>; Definition of similarity
  • <u>ΔABC = ΔRST</u>; By definition of congruency
  • <u>m∠BAC = m∠SRT</u>; by the definition of congruency

Learn more here:

brainly.com/question/11787764

7 0
3 years ago
Find the base of an isosceles triangle whose area is 60 cm² and the length of one of its equal sides is 13 cm. ​
Kobotan [32]

Answer:

Base = 24 cm or 10cm

Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

A=\frac{bh_b}{2}

h_b=\sqrt{a^2-\frac{b^2}{4} }

There are 2 solutions for b

b=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } } ≈ 10cmb=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm

Less complex:

Area of a triangle = 1/2 * b * h = 60

=> h = 120/b

In right triangle ABD

13² = h² + b² /4 ( by Pythagoras law)

=>169 = 120²/b² + b²/4

=>676 b² = 57600 + b^4

=> b^4 - 676 b² + 57600 = 0

=> b² = 676 +- √(676² - 4*57600) / 2

=> b²= 676 +- √(226576) /2

=> b² = (676 +- 476 )/2

=> b² = 1152/2 , 200 /2

=> b² = 576 , 100

=> b = 24, 10

So, Base = 24 cm or 10cm

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2 years ago
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