Material=wall+2*side and material is 40 ft so:
40=w+2s
w=40-2s
Area=ws, using w from above we get:
A=(40-2s)s
A=40s-2s^2
dA/ds=40-4s and d2A/ds2=-4
Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum.
dA/ds=0 when 4s=40, s=10 ft
And since w=40-2s, w=20 ft
So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall. And the maximum possible area is thus 200 ft^2
To determine which system of equations would have the same solution, we evaluate each system of equations.
System 1 4x − 5y = 2, 3x − y = 8
x = 38/11
y = 26/11
<span>System 2 4x − 5y = 2, 3x − 2y = 1
x = 1/7
y = -2/7
System 3 4x − 5y = 2, 3x − 8y = 4
x = -4/17
y = -10/17
System 4 4x − 5y = 2, 10x − 9y = 4
x = 1/7
y = -2/7
</span><span>
Therefore, the correct answer is option 3. </span><span>System 2 and system 4 are equal, because the second equation in system 4 is obtained by adding the first equation in system 2 to two times the second equation in system 2.
4x− 5y = 2 2( 3x − 2y = 1)
----------------------- 10x - 9y = 4</span>
6x3+49x2+126x+104 (I just simplified it, if it is incorrect I'm sorry I didnt understand what you were asking -,^-)
Answer:
x=-2
y=14
Step-by-step explanation:
-7x=4x+22
-11x=22
x=-2
y=-7(-2)
y=14
