1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Afina-wow [57]
3 years ago
6

Find a simple fraction equal to 0.810 repeating

Mathematics
2 answers:
Bond [772]3 years ago
7 0

Answer:

801/1000

Step-by-step explanation:

german3 years ago
5 0
It’s not 801/100 !!! It’s 81/100 because 0.810 is also equal to 0.81 so in fraction form it becomes 81/100 ;) hope this helps !!!
You might be interested in
Find the area of the polygon ​
katrin [286]

Answer:

just add the area of the triangle(formula 1/2bh) and the area of the square(formula bh)

so 1/2(6*height)+8*7

Step-by-step explanation:

5 0
3 years ago
Five rectangles are arranged from the least to the greatest area and named A, B, C, D, and E in order of increasing area. All di
Hatshy [7]

Given that median area is 15 square units.

Hence rectangle C in the middle has 15 square units.

Its dimensions can be width= 5 and length = 3

SInce B is smaller than C and has the same length, B has lengh of 3 with area = 9 sq units.

D has the same perimeter = 16 units.  Since D is a square, side of D = 4 units.

Now D and E have the same length.  Hence length of E = 4 units.

Width of E = width of C = 5 units.Thus makes the area of E as 20 sq units.

Rectangle A has length =3 and width can be less than 3 since area is smaller than B.

so A has length= 3 width = 2 with area = 6 sq units.

8 0
2 years ago
Rationalise the denominator of (12)/(\sqrt(10)+\sqrt(7)+\sqrt(3))
jasenka [17]

Answer:

\frac{12}{\sqrt{10} +\sqrt{7} +\sqrt{3} }=\frac{6\sqrt{147} +6\sqrt{63}-6\sqrt{210}  }{21 }

Step-by-step explanation:

\frac{12}{\sqrt{10} +\sqrt{7} +\sqrt{3} }

=\frac{12\left( \sqrt{10} -\left( \sqrt{7} +\sqrt{3} \right)  \right)  }{(\sqrt{10}+(\sqrt{7} +\sqrt{3 } ))( \sqrt{10} -( \sqrt{7} +\sqrt{3}))}

=\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right)  }{\sqrt{10^2} -(\sqrt{7} +\sqrt{3})^2}

\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right)  }{10-(10+2\sqrt{21} )} }

=\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right)  }{-2\sqrt{21} }

=\frac{-6\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right)  }{\sqrt{21} }

=\frac{-6\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right)  }{\sqrt{21} } \times\frac{\sqrt{21} }{\sqrt{21} }

=\frac{-6\sqrt{21} \left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right)  }{21 }

=\frac{-6\sqrt{210} +6\sqrt{147} +6\sqrt{63}  }{21 }

=\frac{6\sqrt{147} +6\sqrt{63}-6\sqrt{210}  }{21 }

<u><em>Remark</em></u>:

You can simplify moreover if you want to.

5 0
2 years ago
The volume v, measured in mm3, of an object can be calculated by v=4πr353, where r is the radius of the object. if the radius is
satela [25.4K]

Since the volume of an object = \frac{4}{3}\times \Pi r^{3}

Volume= \frac{4}{3}\times (3.14) (243)^{3}

Volume= 60074091 mm^{3}

8 0
3 years ago
What is 6 as a percent?
mr Goodwill [35]

6 as a percent is 600%.

6 0
3 years ago
Other questions:
  • Expression is equivalent to 5(6x+3y)
    12·2 answers
  • Write the equation of an ellipse with vertices at (7, 0) and (-7, 0) and co-vertices at (0, 1) and (0, -1).
    12·1 answer
  • What are the slope and the y-intercept of the linear function that is represented by the equation?
    13·1 answer
  • Solve 3c + 4 = -4c - 17<br> A. 3<br> B. -3<br> C. 21<br> D. -21
    11·1 answer
  • Whats the area of the triangle below?
    5·2 answers
  • Please help I will give brainliest
    11·2 answers
  • Point CC is located at (4,3)(4,3) on the coordinate plane. Point CC is reflected over the xx-axis to create point C'C ′ . Point
    7·1 answer
  • Anyone please help with this answer please????????
    6·1 answer
  • 1.Construct a linear equation from the following statements.
    9·1 answer
  • Find the slope (rate of change) of each representation. Please explain how you got it.
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!