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Olin [163]
2 years ago
7

Multiply. give your answer in standerd form. (3n^2+2n+4)(2n-1)

Mathematics
2 answers:
astra-53 [7]2 years ago
6 0
The answer is 6n^3+n^2+6n-4 :)
mr Goodwill [35]2 years ago
5 0
The answer is 6n^3+n^2+6n-4 I hope I helped you!
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What number divided by 12 = 7
Y_Kistochka [10]
48 divided by 12 = 7

Because 12x7=48

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Sterling has prepared the following two-column proof below. He is given that ZON 2 XLNO and he is trying to prove that OL 2 ON.
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What grade is this? can you maybe break it down
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How do you write 0.5% as a fraction
bixtya [17]
1/2 in simplest form
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Me being dumb ✌️
Inessa05 [86]

Answer:

3  

Step-by-step explanation:

you can do it sequentially and find a potential solution; when you divide the thing, it looks like this

    __2_3_4_0_8________________  

4    | 936_2

       4

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      12

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7 0
3 years ago
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What percentage of the semi circle is shaded? <br>​
mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%

r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\% (1)

Where:

  • A_{h} - Area of the half cross, in square centimeters.
  • A_{s} - Area of the semicircle, in square centimeters.
  • r - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100

r \approx 23.606\,\%

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0
2 years ago
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