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iren [92.7K]
3 years ago
8

2|3x + 5| = -10 how break it down

Mathematics
1 answer:
iren2701 [21]3 years ago
6 0
2|3x + 5| = -10 . Divide both sides by 2:

|3x + 5| = -5 ===>3x+5=-5 & -3x-5=-5 In both cases x=0 
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A car rental agency Advertise renting a car for $24.95 per day and $.33 per mile is Kevin rent the car for today how many whole
pychu [463]

Answer:

Kevin can drive 681 miles.

Step-by-step explanation:

In order to find the amount that he can drive in one day and only pay $250, we have to write an equation for the cost. Using x as the miles he drive, we can express the equation as:

y = .33x + 24.95

Now, we can plug in 250 for y.

250 = .33x + 24.95

225.05 = .33x

681.97 = x

Since we are looking for only whole miles, we have to round down to 681.

6 0
2 years ago
What is the square root of 8
miss Akunina [59]

Answer:

2.82842712475

Step-by-step explanation:

did this help you

4 0
3 years ago
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Oscar has 6 tubular neon lights in order to spell out the word VISION to promote his lighting business.It costs £2 to add a corn
anyanavicka [17]
It is £15 for the words, but I don’t understand the second part
8 0
2 years ago
I. Tell whether each statement is TRUE or FALSE. Refer to the figure below. Write your answer on the space provided.
Vika [28.1K]

Answer:

1. TRUE

2. TRUE

3. TRUE

4. TRUE

5. FALSE

6. TRUE

Step-by-step explanation:

1. From the diagram, we have that m∠2 and m∠7 are alternate interior angles

If m∠2 = 70° and m∠7 = 70°, then we have;

m∠2 = 70° = m∠7

m∠2 = m∠7

Therefore, the alternate interior angles of the lines l₁, and l₂ are equal, and therefore, the lines l₁ and l₂ are parallel, l₁ ║ l₂

TRUE

2. If m∠3 = 90° and m∠7 = 90°, therefore, the angle formed by the intersection of l₃ and l₂ = 90°

Therefore l₃ ⊥ l₂

TRUE

3. m∠5 and m∠7 are corresponding angles

If m∠5 = 85° and m∠7 = 85°, then, m∠5 = m∠7

Therefore, the corresponding angles formed by the lines l₁ and l₂ are equal, therefore;

l₁ ║ l₂

TRUE

4. Whereby we have, m∠1 = m∠5, we get;

m∠1 + m∠5 = 180° by sum of angles on a straight line

∴ m∠1 + m∠5 = m∠1 + m∠1 = 2·m∠1 = 180°

m∠1 = 180°/2 = 90°

∴ m∠1 = 90° = m∠5, and l₃ ⊥ l₁

TRUE

5. m∠1 and m∠8 are alternate exterior angles

If m∠1 = 98° and m∠8 = 82°

∴ m∠1 ≠ m∠8 and l₁ ∦ l₈

FALSE

6. Given that l₁║ l₂, then the angle formed between l₁ and l₃ will be equal to th angle formed between l₂ and l₃

Therefore;

If l₁║ l₂, and l₃ ⊥ l₁, then l₃ ⊥ l₂

(If l₁║ l₂, and l₃ is perpendicular to l₁, then l₃ is also perpendicular to l₂)

TRUE

3 0
2 years ago
1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
3 years ago
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