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belka [17]
3 years ago
6

Find the sum of the hundreds digit and the tenths digit in the number 1,764.823.

Mathematics
2 answers:
goblinko [34]3 years ago
6 0
1,800 and 60 I would believe since we're rounding
Dmitry [639]3 years ago
3 0

Answer:

The answer is 15

Step-by-step explanation:

The hundreds digit is 7 and the tenths digit is 8 and their sum is 15.

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The ratio of males to females at a party is 3 : 5
EastWind [94]
If there are 12 more females and the ratio is two up in favour of females that means that 1 equals to 6, so there are 30 females and 18 males. (30 + 18 = 48)
6 0
2 years ago
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What is the volume of a box that is 16 by 14?​
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I need the length, width, and height

Step-by-step explanation:

3 0
3 years ago
There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
How do you solve -k/5 times 7/5
Firdavs [7]

Answer:

\frac{-7}{25}k

Step-by-step explanation:

\frac{-k}{5} *\frac{7}{5}

just multiply across

-k*7=-7k

5*5=25

\frac{-7}{25}k

hope this helps

5 0
2 years ago
P/5 = 10 what is p
Sav [38]

Answer:

50

Step-by-step explanation:

p/5=10

Your main goal is to isolate p

p/5 = 10, in order to eliminate the 5, multiply 5 on both sides, since it's the inverse of division.

(5)p/5 = 10(5)

p=50

7 0
3 years ago
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