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lara31 [8.8K]
2 years ago
9

When creating a right triangle using 3 squares as seen in the online video, which sides create the right angle in the triangle?

Mathematics
1 answer:
rodikova [14]2 years ago
5 0

When creating a right triangle using three squares, the sides of the two squares with the smallest areas will create the right angle in the triangle (see image attached below).

<h3>Creating a Right Triangle with Three Squares</h3>

The right angle of a right triangle is formed by the two small legs of the right triangle that are perpendicular to each other.

Just like in the diagram attached below, the two squares with the smallest sides will form the right angle in the right triangle.

Therefore, we can conclude that when creating a right triangle using three squares, the sides of the two squares with the smallest areas will create the right angle in the triangle.

Learn more about right triangle on:

brainly.com/question/2437195

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Ymorist [56]
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The product of 3 consecutive even integers is equal to the cube of the first plus the square of the second plus twice the square
algol [13]

Answer:

6, 8 and 10  and  -2, 0, 2

There are two roots x = -2 and 6,    

but the since I don't believe 0 is an even number the answer is 6, 8 and 10

I was incorrect according to G0ggle zero is an even number so another answer is  -2, 0, 2

Step-by-step explanation:

read the question and convert the English to mathematics

x, y and z    even consecutive number

y = x+2

z = y+2 = x+4

and

xyz = x³ + y² + 2z²                                   substitiute x terms  in for y and z

x(x+2)(x+4)  = x³ + (x+2)² + 2(x+4)²           solve for x by graphing on DEMOS

                                                                 x = -2, 6  solved algebraically below

x = -2   y=0   z=2

x = 6    y=8   z=10

Checked both answers

xyz = x³ + y² + 2z²

-2(0)2 = -8 + 0 + 8                  when x = -2

   0   =  0

and

6(8)(10)  =  6³ + 8² +2(10)²      when x = 6

   480   =  216+64+200

             =  480

x(x+2)(x+4)  = x³ + (x+2)² + 2(x+4)²                           solved algebraically

(x²+2x)(x+4)   = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + 3x² + 20x + 36

      3x² - 12x - 36 = 0         factor out the 3

      3[x² - 4x - 12] = 0

       3(x+2)(x-6) = 0     x = -2 and -12

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Can someone please help me thanks :)
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