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3 years ago

How do you write 89,700,000,000 in scientific notation? _× 10^__

Mathematics

2 answers:

Likurg_2 [28]3 years ago

8 0

Answer:

8.97 * 10 ^10

Step-by-step explanation:

We want one nonzero digit to the left of the decimal

8.97

We moved the decimal 10 places to the left

The exponent is positive 10 since we moved 10 places to the left

8.97 * 10 ^10

Vlad [161]3 years ago

5 0

Answer:

It's written as

$89.7 \times {10}^{9}$

$8.97 \times {10}^{10}$

Hope this helps you

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oee [108]

Answer: (assuming the first three terms are -6, -2, 2)

(a) f(n) = 4n - 10

(b) 30

Step-by-step explanation:

(So, just as a preface, I made this answer assuming the first three terms are -6, -2, and 2 since I couldn't find a provided fourth term as the problem said)

(a) In order to create an equation for an arithmetic sequence, you need to find the common difference(d) and the 0th term. You can find the common difference by finding the difference between two consecutive terms:

2 - (-2) = 4 (or (-2) - (-6) = 4), so d = 4

Now, you need to find the 0th term. To do this, you can just subtract the d from the first term, -6:

-6 - 4 = -10.

At this point, you can write the equation:

f(n) = -10 + 4n (this is the 0th term plus the common difference, 4, times the nth term)

f(n) = 4n - 10 (reorganize by value of exponents)

(b) In order to find the 10th term, you just need to plug it into the previous equation:

where n = 10, and f(n) = 4n - 10,

f(n) = 4(10) - 10 (substitute n into the equation)

f(n) = 40 - 10 (multiply the term in the parenthesis by the constant)

f(n) = 30 (subtract)

8 0

3 years ago

Determine which values of p the following integrals converge. Give your answer in each case by selecting the appropriate inequal

sashaice [31]

Answer:

Step-by-step explanation:

$\int\limits^2_1 {\frac{1}{x(lnx)^p} } \, dx$

this can be done by substitute lnx = u

dx/x = du

When x =1, u =0 and when x =2, u = ln 2

So integral = $\int\limits^{ln2} _0 {du/u^p} \\\=\frac{u^{-p+1} }{-p+1}$

We find that this integral value is not definid for p =1

Hence for values of p other than 1, this converges.

When we substitute limits

$\frac{1}{1-p} ((ln2)^{1-p} -1)$

and converges for p ≠1

b) $\int\limits^1_0 {lnx}/x^p \, dx \\\int \frac{\ln \left(x\right)}{x^p}dx=\frac{1}{-p+1}x^{-p+1}\ln \left(x\right)-\frac{x^{-p+1}}{\left(-p+1\right)^2}+C$

So not converging for p =1

But ln x is defined only for x >0

So integral 0 to 1 makes this integral not valid and hence not convergent.

7 0

4 years ago

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Yuri [45]

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5 0

3 years ago

Is the absolute value of ab equal to the absolute value of a divided the absolute value of b?

Serggg [28]

They can be equal if the absolute value of b is 1.

3 0

4 years ago

Read 2 more answers

2x = 4x - 8 show work

Marianna [84]

Answer:

x = 4

Step-by-step explanation:

2x = 4x - 8

subtract 2x from both sides of the equation

2x - 2x = 4x - 2x - 8

0 = 2x - 8

add 8 to both sides of the equation

0 + 8 = 2x - 8 + 8

8 = 2x

divide both sides of the equation by 2

8/2 = 2x/2

4 = x

5 0

3 years ago

How do you write 89,700,000,000 in scientific notation? ___× 10^____

How do you write 89,700,000,000 in scientific notation? _× 10^__