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Umnica [9.8K]
3 years ago
12

Two figures that have the exact same size and shape are

Mathematics
2 answers:
Serhud [2]3 years ago
4 0

Two congruent objects always have either the same shape or mirror image shapes, and have the same size. Objects that have the same shape or mirror image shapes are called geometrically similar, whether or not they have the same size.


hope this helps!

AnnZ [28]3 years ago
3 0

Howdy!

2 shapes that have the exact same size and shape are CONGRUENT.

Have a nice day, Jesus loves you.

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PLEASE HELP ME!!!!!!!!
GREYUIT [131]

Answer:

  The solution to the system of equations (x, y) = (2, 4) represents the month in which exports and imports were equal. Both were 4 in February.

Step-by-step explanation:

We're not sure what "system of equations" is being referenced here, since no equations are shown or described.

__

Perhaps your "system of equations" is ...

  f(x) = some equation

  g(x) = some other equation

Then the solution to this system of equation is the pair of values (x, y) that gives ...

  y = f(x) = g(x)

If x represents the month number, then the solution can be read from the table:

  (x, y) = (2, 4)

This is the month in which exports and imports were equal. Both numbers were 4 in February.

7 0
3 years ago
If Mr. Callahan expects to sell 150 bunches of flowers next week, which is the best prediction of how many bunches of daffodils
djyliett [7]
28, because 150/7 is about 21 and 28 is the closest answer. I would need more info for it to be a definite answer but that is what I would choose. Hope I helped!

7 0
3 years ago
50+30 x12 20 POINTS GUYS YESSSSSSSSSSSSSSSSSSSSSSS
daser333 [38]

Answer:

960

Step-by-step explanation:

50+30= 80

80x12=960

8 0
3 years ago
Read 2 more answers
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The answer is B, -12p² - 12pq + 2p - 3q² + q. You have to distribute each term using FOIL, which is First, Outside, Inside, and Last. Then you have to combine like terms and order the variable correctly.
3 0
3 years ago
A telephone survey uses a random digit dialing machine to call subjects. the random digit dialing machine is expected to reach a
yanalaym [24]
P(r successes in n trials) = ⁿC_{r}×[P(Success)^{r}]×[P(failure)]^{n-r}

We have
n=8
r=2
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P(Failure)=0.85

Substitute these values into the formula, we have
P( 2 success in 8 trials) = ⁸C₂ × (0.15)² × (0.85)⁶
P( 2 success in 8 trials) = 0.2376.... ≈ 0.24 = 24%
6 0
3 years ago
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