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QveST [7]
3 years ago
8

Pam put pink frosting on one-fourth of the cookies she made.If y is the total number of cookies she made,which expression shows

the number of cookies with pink frosting?
A.1/4
B.1/4+y
C.y-1/4
D.y÷1/4​
Mathematics
1 answer:
Licemer1 [7]3 years ago
7 0

Answer:

the answer is b hope it helpssssss

Step-by-step explanation:

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En un huerto se siembra frijol. Si se pone una planta, produce 3kg de frijol. por cada planta extra que se ponga, todas las plan
Ad libitum [116K]

Answer:

y = -0.07x2 + 3.07x

Step-by-step explanation:

For each plant we add, there is a decrease of 70 grams for all plants from the inicial value of 3 kg of beans.

So, for 2 plants, we have (3 - 0.07) * 2

For 3 plants, we have (3 - 2*0.07) * 3

For x plants, we have (3 - (x-1)*0.07) * x

So we can model the final result of the amount of beans 'y' with the equation:

y = (3 - (x-1)*0.07) * x

y = (3 - 0.07x + 0.07) * x

y = (3.07 - 0.07x) * x

y = -0.07x2 + 3.07x

(In this equation we have a = -0.07, b = 3.07 and c = 0)

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3 years ago
How to factor <br><img src="https://tex.z-dn.net/?f=3x%20-%203" id="TexFormula1" title="3x - 3" alt="3x - 3" align="absmiddle" c
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Take out common factor, 3 :

3x - 3 = 3(x - 1)

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Answer: 3(x - 1)
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3 years ago
A ribbon is 10 yards long. How many 4 inch pieces cut be cut?
Sever21 [200]
1 yard=3 feet
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3 years ago
Y=4x+3 table of ordered pairs
lara31 [8.8K]

Answer:

X:1 2 3 4 5 Y:7 11 15 19 23.

Step-by-step explanation:

We just need to put in the values of x into the equation: y = 4x + 3.

<u>x = 1: </u>

y = 4(1) + 3

  = 4 + 3

y = 7

<u>x = 2: </u>

y = 4(2) + 3

  = 8 + 3

y = 11

<u>x = 3:</u>

y = 4(3) + 3

  = 12 + 3

y = 15

<u>x = 4:</u>

y = 4(4) + 3

  = 16 + 3

y = 19

<u>x = 5:</u>

y = 4(5) + 3

  = 20 + 3

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6 0
3 years ago
Some help figuring out the answer?? Also explain a little how you got there
ipn [44]

9514 1404 393

Answer:

  x = 10·cos(θ) -4·cot(θ)

Step-by-step explanation:

Apparently, we are to assume that the horizontal lines are parallel to each other.

The relevant trig relations are ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

If the junction point in the middle of AB is labeled X, then we have ...

  sin(θ) = 4/BX   ⇒   BX = 4/sin(θ)

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Then ...

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Substituting for BX and XA using the above relations, we get

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Solving for x gives ...

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_____

We used the identity ...

   cot(θ) = cos(θ)/sin(θ)

6 0
3 years ago
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