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ololo11 [35]
3 years ago
13

Q1) If Q is directly proportional to P and Q = 28 when P = 4, (i) express Q in terms of P, (ii) find the value of Q when P = 5,

(iii) calculate the value of P when Q = 42.
Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer: i) Q=7*P   ii) if P=5 => Q=35 iii) if Q=42 => P=6

Step-by-step explanation:

Q is directly prportional to P that means that

Q/P=k=const ( where k is the prportionality coefficient)

So k= 28/4=7

So i)  Q= 7*P

ii) Q=5*7=35 if P=5 =>Q=35

iii) P=42/7=6   if Q=42 => P=6

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A gym memebership costs a flat fee of $68 and an additional $19.99 per month.Since she became a member Ellen has paid the gym $2
fomenos

Answer:

She has been a member of the gym for seven months

Step-by-step explanation:

In this question, we are asked to calculate the number of months a customer has been a member of a gym, given the pricing template of the gym.

Now, as we can see from the question, there are two kinds of fees to be paid. The flat fee and the subscript class.

First, let’s represent the number of months she has been a member of the gym by m. This means the total amount of money she has paid for m months would be m * 19.99m

Now, recall, we have a flat fee of $68, adding this to the total monthly payment for m months bring the wages to 19.99m + 68

This is said to equal $207.93

This means;

19.99m + 68 = 207.93

19.99m = 207.93 -68

19.99m = 139.93

m = 139.93/19.99 = 7

3 0
3 years ago
What is the range of the dataset 12,12,12,12,12
Igoryamba

Answer:

0

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
5x + 3<br> ----------<br> 15 <br><br><br> How is this solved?
Bas_tet [7]
This expression can't be simplified any further be as there is no common factor for the numerator and the denominator.
8 0
3 years ago
5x6-2x3 where would i put the ( ) to make 84
krok68 [10]
(5*6-2)*3 = 84
(30-2)*3
28*3 = 84
well explained by hacker below
6 0
4 years ago
Read 2 more answers
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