Why does (x=m)2 + (y-d)2=s2 make a circle

Pls help and show workings

Galina-37 [17]

Answer:

orufo45o94590i-039i902

Step-by-step explanation:

4 0

3 years ago

Graph the line with the equation y = - 1/3X + 2

BlackZzzverrR [31]

Answer:

the graph ^

Step-by-step explanation:

this is fun for no reason

7 0

3 years ago

The front of a house is composed of a trapezoid and a rectangle. The height of the rectangle is 12 feet. The base of therectangl

choli [55]

Drawing of the description:

To get the total area, we have to calculate the area of the rectangle and trapezoid, and then add them.

• Area of rectangle

$A_r=b\times h$ $A_r=30\times12=360ft^2$

• Area of trapezoid

$A_t=\frac{1}{2}h\cdot(b_1+b_2)$ $A_t=\frac{1}{2}\cdot15\cdot(30+15)=\frac{15}{2}\cdot(45)=337.5ft^2$

• Area of the front of the house

Finally, to get the total area we add them:

$A_T=360+337.5=697.5ft^2$

Answer: 697.5 ft²

8 0

2 years ago

The table shows the distance Allison drove on one day of her vacation. Is the relationship between the distance and the time a p

Anuta_ua [19.1K]

Answer:

we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

Step-by-step explanation:

We know that when 'y' varies directly with 'x', we get the equation

y ∝ x

y = kx

k = y/x

where 'k' is called the constant of proportionality.

In our case, the table shows the distance Allison drove on one day of her vacation.

Time (h) 1 2 3 4 5

Distance (mi) 55 100 165 280 250

using the equation

k = y/x

susbtitute y = 55, x = 1

k = 55/1 = 55

substitute y = 100, x = 2

k = y/x

k = 100 / 2 = 50

substitute y = 165, x = 3

k = y/x

k = 165 / 3 = 55

substitute y = 280, x = 4

k = y/x

k = 280 / 4 = 70

substitute y = 250, x = 5

k = y/x

k = 250 / 5 = 50

It is clear that the value of 'k' does not remain constant.

Therefore, we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

6 0

3 years ago

A devastating freeze in California’s Central Valley in January 2007 wiped out approximately 75% of the state’s citrus crop. It t

inna [77]

The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.

The linear equation of the function is: $g(P) =22.9P +7$ , while its inverse is: $g^{-1}(c) = \frac{c - 7}{22.9}$ .
The domain is from 0% to 100%, while the range is from 7 to 29.9