3 years ago

I need help with this question pic is above

Mathematics

1 answer:

zavuch27 [327]3 years ago

6 0

A: peak
B: falling
C:on the ground

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What are the real roots of 2x^3-42x-40

malfutka [58]

2x^3-42x-40=0
2x^3-42x=40
2x(x^2-21)=40
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3 years ago

What are the coefficients in the following expression 8x + 5 + 6y

erastovalidia [21]

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8 5 and 6 are the coefficients

Step-by-step explanation:

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I need the answer hurry plz

zaharov [31]

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350 ?

Step-by-step explanation:

500 - 150 = 350

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2 years ago

F(x)=3x-8

iVinArrow [24]

What this is asking is for you to plug values into the following function: $f(x)=\frac{3x-8}{6x}$

Since the question is asking you to find $f(3)-f(1)$ , this is how you work it out:
You take the function;
$f(x)=\frac{3x-8}{6x}$
And plug the numbers indicated in for x;
$f(x)=\frac{3x-8}{6x}\\
f(3)=\frac{3(3)-8}{6(3)}\\
f(3)=\frac{9-8}{18}\\
f(3)=\frac{1}{18}\\\\
f(1)=\frac{3(1)-8}{6(1)}\\
f(1)=\frac{3-8}{6}\\
f(1)=\frac{-5}{6}\\\\
Now\ what\ you\ do\ is\ you\ subract\ f(3)\ and\ f(1).\\
f(3)-f(1)\\
f(3)-f(1)=\frac{1}{18}-\frac{-5}{6}\\
f(3)-f(1)=\frac{1}{18}-\frac{-15}{18}\\
f(3)-f(1)=\frac{1+15}{18}\\
f(3)-f(1)=\frac{16}{18}=\frac{8}{9}$
So the answer to f(3) - f(1) = $\frac{8}{9}$

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2 years ago