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boyakko [2]
3 years ago
8

In April, a customer buys 1 MCS Oct 50 call for 9 and sells 1 MCS Jul 50 call for 4. What will the customer's profit or loss be

if he buys back the July call for $1 and sells the October call for $12?
Mathematics
1 answer:
Alexandra [31]3 years ago
5 0

Answer:

The net gain or profit is $600

Step-by-step explanation:

Firstly, we should know the losses of the customer which were:

9 when the customer bought 1 MCS Oct 50

1 when the customer bought back 1 MCS Jul 50

Therefore the total losses were 10.

And the gains were:

4 when the customer sold 1 MCS Jul 50

12 when the customer sold 1 MCS Oct 50

Therefore the total gains were 16.

Therefore (16 - 10)×100 = $600

Therefore the net gain or profit is $600

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5x + 6y when x = 16, y = -9
atroni [7]

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Determine, using the intermediate value theorem, if the function F(x)=x^3+2x-1 has a zero on the interval [0,1]. Justify your an
SSSSS [86.1K]

Plug x = 0 into the function

f(x) = x^3 + 2x - 1

f(0) = 0^3 + 2(0) - 1

f(0) = -1

Note how the result is negative. The actual number itself doesn't matter. All we care about is the sign of the result.

Repeat for x = 1

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This result is positive.

---------------------------

We found that f(0) = -1 and f(1) = 2. The first output -1 is negative while the second output 2 is positive. Going from negative to positive means that, at some point, we will hit y = 0. We might have multiple instances of this happening, or just one. We don't know for sure. The only thing we do know is that there is at least one root in this interval.

To actually find this root, you'll need to use a graphing calculator because the root is some complicated decimal value. Using a graphing calculator, you should find the root to be approximately 0.4533976515

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3 years ago
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marishachu [46]

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6 0
2 years ago
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