Answer:
0.014 or 1.4% of connectors fail during the warranty period.
Step-by-step explanation:
Consider the provided information.
Let: D = electrical connector is dry
D' = electrical connector is not kept dry (i.e., is wet)
F = connector fails during warranty period
F' = connector does not fail during warranty period
90% of the connectors are kept dry
That means P(D)=0.9
10% are wet,
P(D')=0.1
The probability is 1% that an electrical connector that is kept dry fails during the warranty period, i.e.
P(F|D)=0.01
If the connector is ever wet, the probability of a failure during the warranty period is 5%, i.e.
P(F|D')=0.05
Hence, 0.014 or 1.4% of connectors fail during the warranty period.
Answer:
The second table.
Step-by-step explanation:
In the first table, the speed goes from 45 down to 43; then down to 41; then up to 42; then up to 43. It decreases and then increases. This is not the correct table.
In the second table, the speed goes from 45 up to 47; then up to 49; then down to 48; then down to 47. It increases and then decreases; this is the correct table.
To verify, we check the last two tables. The third table stays at 45, then decreases to 43 and 41. This is not correct.
The last table decreases from 45 to 43, then decreases to 41, then stays constant. This is not correct.
The second table is the only correct one.
Full bubble at 0, then make it go right.
Answer:
V≈20.94
Step-by-step explanation:
The formula for solving the volume of a cone is V=πr^2(h/3).
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