F(x)=x2,
g(x)=f(3x)=(3x)2=9x2
Now to graph y=9x2. This is a parabola (U-shape), vertex at (0, 0), symmetric aroung y axis. When x=1/3 or -1/3, then y=1.
So, try to draw the graph.
1 subtract 1 2m - 1 = 3m
<span>2 subtract 2 2m = 1 + m </span>
<span>3 subtract m m - 1 = 2 </span>
<span>4 add 2 + m = 3 </span>
<span>5 subtract 2m -2 + m = 1 </span>
<span>6 add 1 3 = 1 + m
1.5.
2.4
3.1
42
56
63</span>
You need to multiply the four numbers and then takeway
Answer:
fog = 2√(x-1) + 1
Domain = [1,
)
Step-by-step explanation:
Given the functions f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog
fog = f(g(x))
f(g(x)) = f(√(x-1))
f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)
f(√(x-1)) = 2(√(x-1))+1
f(√(x+1)) = 2√(x-1) + 1
fog = 2√(x-1) + 1
<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>
If x-1≥0
x≥0+1
x≥1
This means the range of variable x must be values of x greater than or equal to 1.
Domain = [1,
)