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MariettaO [177]
3 years ago
14

Help please help me please

Mathematics
2 answers:
lakkis [162]3 years ago
6 0
B. Because if you add 10+9=19, that's the side of a small side, so it wouldn't make since if you chose A. right? and it can't be D. because that's too high
lesantik [10]3 years ago
4 0
The answer will be A.4, saying that the units 10 and 9 had to be added then subtracted by 15. 

Hope this helps :)
  Brainliest please.
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The function h(t) = –16t2 + 96t + 6 represents an object projected into the air from a cannon. The maximum height reached by the
jolli1 [7]
If you've started pre-calculus, then you know that the derivative of  h(t)
is zero where h(t)  is maximum.

The derivative is            h'(t) = -32 t  +  96 .

At the maximum ...        h'(t) = 0

                                       32 t = 96 sec

                                           t  =  3 sec . 
___________________________________________

If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.

In that case, the question GIVES you the maximum height.
Just write it in place of  h(t), then solve the quadratic equation
and find out what  't'  must be at that height.

                                       150 ft = -16 t²  +  96  t  +  6 

Subtract 150ft from each side:    -16t²  +  96t  -  144  =  0 .

Before you attack that, you can divide each side by  -16,
making it a lot easier to handle:

                                                         t²  -  6t  +  9  =  0

I'm sure you can run with that equation now and solve it.    
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.  
(Funny how the two widely different methods lead to the same answer.)

The answer is from AL2006

6 0
3 years ago
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sukhopar [10]

Answer:

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Step-by-step explanation:

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What is the most precise
Maru [420]
It is d i would include a visual picture but i’m lazy lol
7 0
3 years ago
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