Determine the number of real solutions for the equation: 6x^2+8x=7
1 answer:
Answer:
Step-by-step explanation:
You could factor this to find out how many real roots you have, but it's easier to use the rule of the discriminate. The discriminate comes from the quadratic formula:
Plug in the numbers from the quadratic and see what the value of it is. If the:
discriminate < 0, you have 2 imaginary roots
discriminate = 0, you have 1 real root, multiplicity 2 and
discriminate > 0, you have 2 real roots
Our b is 8, our a is 6 and our c is -7 (remember you have to set the polynomial equal to 0 to do this).
Because 232 is > 0, we have 2 real roots.
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Given :
A holiday meal cost 12.50 a person plus a delivery fee of $30 at we cater.
The same meal cost $15 a person with no fee at Good Eats.
To Find :
When does we cater become the better deal.
Solution :
Let , x is number of order .
Cost at cater , C = 12.5x + 30 .
Cost at Good Eats , G = 15x .
We need to find :
G > C
Therefore, after 12th order cater will be more value for money.
Hence, this is the required solution.
Answer:
Third option.
Step-by-step explanation:
You need to cube both sides of the equation. Remember the Power of a power property:
According to the Product of powers property:
Then. simplifying you get:
Now you need to compare the exponents. You can observe that the exponent of "x" on the right side is 6, then the exponent of "x" on the left side must be 6. Therefore:
You can notice that the exponent of "y" on the left side is 5, then the exponent of "x" on the left side must be 5 too. Therefore "d" is: