Answer:
<h2>16kg</h2>
Step-by-step explanation:
This problem is borers on elasticity of materials.
according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

where F is the applied force in N
k is the spring constant N/m
e is the extension in meters
Given data
mass m= 24kg
extensnion=15cm in meters=
= 
we can solve for the spring constant k
we also know that the force F = mg
assuming 
therefore

We can use this value of k to solve for the mass that will cause an extension of 

Answer:
K = 
Step-by-step explanation:
P = KTV
Divide both sides by TV
(P/TV) = K
Answer:
$160
Step-by-step explanation:
80 * $2
$160
Answer: $160
B.
The line starts at the origin and goes down by two.
Answer:
I can't see the options but the answer is -1,024
Step-by-step explanation:
-4^5= -4 × (-4) × (-4) × (-4) × (-4)= -1,024