6x + 18y = 18. Let us take x = 0
6(0) + 18y = 18
0 + 18y = 18
18y = 18
y = 18/18
y = 1
(0, 1) [x = 0, y = 1]
6x + 18y = 18. Let us take y = 0
6x + 18(0) = 18
6x + 0 = 18
6x = 18
x = 18/6
x = 3
(3, 0) [x = 3, y =0]
Infinite solutions can be found for x and y
The difference between the 6th term and the 9th term of the sequence is 135
<h3>How to determine the difference</h3>
Given that the nth term is;
3n² + 11
For the 6th term, the value of n is 6
Let's solve for the 6th term
= 3( 6)^2 + 11
= 3 × 36 + 11
= 108 + 11
= 119
For the 9th term, n = 9
= 3 (9)^2 + 11
= 3( 81) + 11
= 243 + 11
= 254
The difference between the 6th and 9th term
= 254 - 119
= 135
Thus, the difference between the 6th term and the 9th term of the sequence is 135
Learn more about algebraic expressions here:
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4) (log3)14/(log3)4
hope dis helps<span />
Answer:
D.5/14
Because 4 appeared five times over the total
