If the price of an object dropped 75% down to $85.99 what was the original price?

1 answer:

6 0

If the price of an object drastically dropped 75%, then the dropped price is equal to 25% of the original price. That means that to find the original price, we have to multiply by the reciprocal of 25% (4). The original price would be $85.99 * 4 which is $343.96.

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Determine the type and number of solutions of 4x^2-5x+1=0

MA_775_DIABLO [31]

4x^2-5x=-1

$\sqrt{4x^2-5x} = \sqrt{-1}$ 4x^2-5x+1=0

4x+2.24x=1

6.24x=1

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7 0

3 years ago

Anmol got 60 marks out of 80 marks in mathematics what percent marks did he get

Kay [80]

Answer:

75%

Step-by-Step Explanation:

There are two ways to go about this.

1) We can simply put it as a fraction = 60/80.

Then since a fraction sign also means division, we divide 60 by 80 = 0.75

Then to change a decimal into a percentage, we multiply by 100% = 75%

So our answer is 75%

2) We can simply it after it is put into a fraction = 60/80 = 3/4

It should be common knowledge that 3/4 is 75% depending on what grade you are in.

But there you have it, whichever way you prefer, the answer is always 75%.

3 0

3 years ago

A quadrilateral has vertices A, B, C, and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units

Kryger [21]

Answer:

The correct option is O B'

Step-by-step explanation:

We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.

Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.

In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.

Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).

I will attach a drawing with an example.

Finally, we only have to look at the vertices and its original distances to answer the question.

The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'