Answer:
Step-by-step explanation:
-The locust population grows by a factor and can therefore be modeled by an exponential function of the form:
Where:
is the population after t days.
is the initial population given as 7600
is the rate of growth
is time in days
-Given that the growth is by a factor of 5( equivalent to 500%), the r value will be 5
-The population increases by a factor of 5 every 22 days. therefore at any time instance, t will be divided by 22 to get the effective time for calculations.
Hence, the exponential growth function will be expressed as:
The picture in the attached figure
we know that
RX+RA+XA=24
XA=24-RA-RX------> XA=24-11-4----> XA=9
XA=XP+PA
so
XP+PA=9------> XP=9-PA-----> equation 1
RX/XP=RA/PA
11*XP=4*PA-----> equation 2
substitute equation 1 in equation 2
11*[9-PA]=4*PA-----> 99-11*PA=4*PA----> 15*PA=99----> PA=99/15
PA=6.6
XP=9-PA-----> XP=9-6.6----> XP=2.4
the answer is the option<span>
B. XP = 2.4, PA = 6.6 </span>
Find the volume of the cylinder and divide by 2:
V = pi * r^2 * h
V = 3.14 * 11^2 * 17
V = 6458.98
Divide by 2 since it's half full:
6458.98 / 2 = 3229.49
Now divide it by 46.2 to see how long it will take to drain out:
3229.49 / 46.2 = 69.902
So it will take approximately 70 seconds to drain out.
Answer:
145 yd²
Step-by-step explanation:
There will be dour triangular faces. For a triangle, area is given as
A=½bh where b is base and h is height. The base will be 5 yards and h is 12 yards hence for one triangular face, area will be ½*5*12=30 yd²
Since they are four similar triangles, area of triangular faces will be 30*4=120 yd²
The surface area of a square base is given by
A=a*a=a² where a is the dimension of one side. Given that the meaurement is 5 yards then A=5²=25 yd²
Total area will be the sum of triangular and square faces hence 120+25=145 yd²
